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vazorg [7]
3 years ago
8

A car has a mass of 1.2 tonne. The suspension spring of the car together have a spring constant of 2.0. How for does the weight

of the car compress its spring
Physics
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

x = 58.86[mm]

Explanation:

This problem can be solved by means of Hooke's law which tells us that the force is equal to the product of the constant of the spring by the distance that is compressed or stretched. The following equation can be used.

F=k*x

where:

F = force or weight [N]

k = spring constant = 2*10⁵ [N/m]

x = distance  compressed [m]

The weight can be calculated as the product of the mass by the gravity acceleration.

F=m*g\\F=1.2*1000*9.81\\F=11772[N]

Now replacing in the Hook's law

11772=2*10^{5} *x\\x=0.05886[m]\\x=58.86[mm]

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Consider a one-dimensional crystal (similar to a carbon nanowire) with length 10 um and lattice spacing 0.1 nm.
Finger [1]

Answer:

a)  Fermi level = 600 electron-volts

b) \frac{2.04 * 10^{13} }{\sqrt{E} }

Explanation:

Given data:

length of one-dimensional crystal = 10 um

Lattice spacing = 0.1 nm

A) Determine the Fermi level assuming one electron per atom

Total length = 10 <em>u</em>m

Interatomic separation of a = 0.1 nm

in this case the Atom has one electron therefore the number of electrons = 10^5  and the number of states Ns = gsN = 2 * 10^5  ( attached below is some part of the solution )

hence : Fermi level = 600 electron-volts

B) Determine the density of states as a function of electron energy

attached below is the detailed solution

5 0
3 years ago
A runner traveled 7.7 miles an hour and a half what was their average speed
Alenkasestr [34]

Answer:5.13333333...

Explanation: 7.7 is the distance and an hour and a half is the average speed. You would have to divide the total distance by the total time. So it would be 7.7 divided by 1.5 which would equal 5.13333333333...

6 0
4 years ago
The sides of a square increase in length at a rate of 3 ​m/sec. a. At what rate is the area of the square changing when the side
maks197457 [2]

The area of a square is given by:

A = s²

A is the square's area

s is the length of one of the square's sides

Let us take the derivative of both sides of the equation with respect to time t in order to determine a formula for finding the rate of change of the square's area over time:

d[A]/dt = d[s²]/dt

The chain rule says to take the derivative of s² with respect to s then multiply the result by ds/dt

dA/dt = 2s(ds/dt)

A) Given values:

s = 14m

ds/dt = 3m/s

Plug in these values and solve for dA/dt:

dA/dt = 2(14)(3)

dA/dt = 84m²/s

B) Given values:

s = 25m

ds/dt = 3m/s

Plug in these values and solve for dA/dt:

dA/dt = 2(25)(3)

dA/dt = 150m²/s

6 0
3 years ago
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8 0
3 years ago
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Korolek [52]

Answer:

B. Gauss’s law

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hope this helped!

7 0
3 years ago
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