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astra-53 [7]
3 years ago
5

Consider a one-dimensional crystal (similar to a carbon nanowire) with length 10 um and lattice spacing 0.1 nm.

Physics
1 answer:
Finger [1]3 years ago
5 0

Answer:

a)  Fermi level = 600 electron-volts

b) \frac{2.04 * 10^{13} }{\sqrt{E} }

Explanation:

Given data:

length of one-dimensional crystal = 10 um

Lattice spacing = 0.1 nm

A) Determine the Fermi level assuming one electron per atom

Total length = 10 <em>u</em>m

Interatomic separation of a = 0.1 nm

in this case the Atom has one electron therefore the number of electrons = 10^5  and the number of states Ns = gsN = 2 * 10^5  ( attached below is some part of the solution )

hence : Fermi level = 600 electron-volts

B) Determine the density of states as a function of electron energy

attached below is the detailed solution

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kondaur [170]

Answer:

\boxed {\boxed {\sf 100,000 \ Joules}}

Explanation:

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E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2

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E_k= 1000 \ kg  \times (100 \ m^2/s^2)

Multiply again.

E_k= 100,000 \ kg*m^2/s^2

  • 1 kilogram square meter per square second is equal to 1 Joule.
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E_k= 100,000 \ J

The roller coaster car has <u>100,000 Joules</u> of kinetic energy.

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2 years ago
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