Answer:
6ΔG°(f) H₂O = -229 Kj/mol
Explanation:
4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)
ΔG°(f) 4mol(-16.66Kj/mol) | 5mol(0Kj/mol) || 4mol(+86.71Kj/mol) | 6ΔG°(f) H₂O
Hess's Law
ΔG°(Rxn) = ∑ΔG°(f) Products - ∑ΔG°(f) Reactants
-957.9 Kj = [(4mol(+86.71Kj/mol)) + 6ΔG°(f) H₂O(g)] - [4mol(-16.66Kj/mol) + 5mol(0Kj/mol)]
-957.9 Kj = [4(86.7)Kj + 6ΔG°(f) H₂O] - [4(-16.66)Kj] = 346.84Kj + 6ΔG°(f) H₂O + 66.64Kj
ΔG°(f) H₂O = ((-957.9 - 346.84 -66.64)/6)Kj = -228.56 Kj ≅ -228.6 Kj*
*Verified with Standard Heat of Formation Table
The answer: The answer is B
Answer:
See attached picture.
Explanation:
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In this case, by considering that the carbon has four valence electrons as it is in group IVA, sulfur has six valence electrons as it is in group VIA and bromine has seven valence electrons as it is in group VIIA we infer that the carbon is the central atom in CSBr2 so one double bond between carbon and sulfur makes it complete the octet and two carbon-to-bromine bonds are formed in order to complete the octets of both carbon and bromine as shown on the attached picture.
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Answer: Option (A) is the correct answer.
Explanation:
Atomic number of sodium is 11 and its electronic configuration is
.
In order to gain stability, sodium loses one electron and hence it forms a positive ion
.
Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.