<span>Answer
is: mass of burned butane is 11.6 g.</span>
Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
m(butane)
= 50,0 g.
<span>
V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷
Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) :
n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) =
0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) =
0,2 mol.<span>
m(C</span>₄H₁₀) =
n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) =
0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) =
11,6 g.
A group of environmentalists were discussing the benefits and drawbacks associated with using fossil fuels. Which argument <span>best </span>fits the conversation?
Fossil fuels are cheaper than alternative forms of energy.Fossil fuel reserves will never be depleted.<span>Fossil fuels are easily renewed. </span><span>Fossil fuel use does not affect the environment.</span>
If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.
These consist of glycogen, cellulose, as well as starch. Benedict's reagent can be used as a test to see if there are lots of simple carbohydrates present. When it interacts with lowering sugars, it changes from turquoise to yellow or orange. These contain unbound aldehyde but rather ketone groups in simple carbohydrates.
Sugars and starches are examples of carbohydrates. They contain carbon, hydrogen, and oxygen, which appear in the ratio 1:2:1. Size-based categories for carbohydrates include monosaccharides, disaccharides, or polysaccharides. Carbohydrates act as sources of power as their main purpose.
Therefore, If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.
To know more about carbohydrate
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Mechanical! Hope I helped
Answer:
7.68 × 10²⁴
Explanation:
Step 1: Calculate the mass of 1 molecule of the monomer CH₂CHCN
We will get the mass of the monomer by adding the masses of the elements.
mCH₂CHCN = 3 × mC + 3 × mH + 1 × mN
mCH₂CHCN = 3 × 12.01 amu + 3 × 1.01 amu + 1 × 14.01 amu = 53.07 amu
Step 2: Convert the mass of the monomer to grams
We will use the conversion factor 1 amu = 1.66 × 10⁻²⁴ g
53.07 amu × 1.66 × 10⁻²⁴ g/1 amu = 8.81 × 10⁻²³ g
Step 3: Calculate "n"
We will divide the mass of the polymer by the mass of the monomer.
n = 676.8 g / 8.81 × 10⁻²³ g = 7.68 × 10²⁴
