The extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.
<h3>What is equilibrium?</h3>
Chemical equilibrium refers to the state in which both the reactants and products are present in equal concentrations or amount. In equlibrium, same amount of reactant is converted into product and product into reactant.
So we can conclude that the extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.
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Answer:
When sodium chloride dissolves in water to make a saturated solution there is a 2.5 per cent reduction in volume. ... The solubility of salt does not change much with temperature, so there is little profit in using hot water.
Answer with Explanation:
Small and large carbohydrates have<em> diverse structural properties</em>. Such property allow them to have <u>different solubility.</u>
Solubility is a chemical property of a substance that allows it to dissolve in a given solvent.
Carbohydrates are made up of "monosaccharides." These are simple sugars and are considered small carbohydrates. On the contrary, "polysaccharide" is an example of a large carbohydrate.<em><u> Monosaccharides are soluble in water</u></em><em> </em>while<em><u> many polysaccharides are not soluble in water.</u></em>
The high solubility of monosaccharides is mainly due to the presence of hydroxide (OH) groups. These groups are always ready to bond with water (H₂O). Many polysaccharides are not soluble in water because of <em>intermolecular interactions</em> that prevents it from binding with water. Its dissolution process is different when compared to the smaller molecules.
So, this explains the answer.
<h3>You will pay $ 30876800</h3>
We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:
<h3 />
Density of gold = 19298 oz/ft³
Volume of gold = 1 ft³
<h3>Mass of gold =?</h3>
Density = mass /volume
19298 = mass / 1
<h3>Mass of gold = 19298 oz</h3>
Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:
1 oz = $ 1600
Therefore,
19298 oz = 19298 × 1600
19298 oz = $ 30876800
Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800
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