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mestny [16]
2 years ago
9

Which of these are examples of passive transport? A. osmosis B.diffusion c. endocytosis d.8 mitosis​

Chemistry
1 answer:
AfilCa [17]2 years ago
4 0

Answer:

Passive Transport

Explanation:

The three examples of passive transport are

Diffuison

Osmosis

facilated diffuison

So the answer can be A or B

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Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
1. When you first opened the bottle of coke the pressure of gas in the coke (increased/decreased) and the dissolved gas( stays i
Serga [27]

Answer:

1. When you first opened the bottle of coke the pressure of gas in the coke (increased) and the dissolved gas(leaves) the coke. 2. When you placed the coke in hot water , the pressure of gas in the coke (increased) and the dissolved gas(leaves) the coke 3. Therefore to increase the solubility of a gas in a liquid ( that is to make a gas more soluble in a liquid.

Explanation:

Hope it helps.

3 0
3 years ago
I need some help!!! Asap
miss Akunina [59]

Answer:

Al2O3 + 6HCl --> 2AlCl3 + 3H2O

Explanation:

Al: 2

O: 3

H: 6

Cl: 6

Balanced on both sides.

8 0
3 years ago
8. A 15.0 gram unknown piece of metal at 99 oC is added to 75 grams of water at 23 oC. The final temperature of the metal and wa
Setler79 [48]

The specific heat of the unknown metal is 0.859 J/g⁰C.

<h3>Specific heat of the unknown metal</h3>

Heat lost by the unknown metal = Heat gained by water

m₁c₁Δθ₁ = m₂c₂Δθ₂

where;

  • c₁ is specific heat of the unknown metal
  • c₂ is specific heat of water

(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)

1095c₁ = 940.5

c₁ = 940.5/1095

c₁ = 0.859 J/g⁰C

Learn more about specific heat here: brainly.com/question/16559442

#SPJ1

3 0
2 years ago
According to the activity series, which one of the following reactions will occur?
Korvikt [17]

Answer:

i think

SrF2 + Br2 --->

dont count me on it

Explanation:

balanced

3 0
3 years ago
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