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Crazy boy [7]
3 years ago
12

How can to sticks quickly start a fire​

Physics
1 answer:
LekaFEV [45]3 years ago
8 0

Answer:

The closest thing to "rub bing two sticks together" is the hand-drill. You will need a fireboard (a small cedar board is good) and a thin, straight stick.

Explanation:

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A 1kg mass is thrown to a height of 2cm. what is the potential energy​
prohojiy [21]
  • Mass=m=1kg
  • Height=h=2cm=0.02m
  • Acceleration due to gravity=g=10m/s^2

\\ \tt\hookrightarrow P.E=mgh

\\ \tt\hookrightarrow PE=1(10)(0.02)

\\ \tt\hookrightarrow PE=0.2J

4 0
2 years ago
Read 2 more answers
14. What is the mass of a 250 N bag of groceries?
Veseljchak [2.6K]

Answer:

mass = 25.5kg

Explanation:

The gravitational force equivalent, or, more commonly, g-force, is a measurement of the type of force per unit mass – typically acceleration – that causes a perception of weight, with a g-force of 1 g equal to the value of gravitational acceleration on Earth, g, of about 9.8 m/s².

Mass, m = \frac{Force}{acceleration due to gravity}

mass,m=\frac{F}{g} = \frac{250}{9.8}= 25.5 kg

8 0
3 years ago
If the labor force of 155 million people is growing by 1.0 percent per year, how many new jobs have to be created each month to
dybincka [34]

First let us compute for the total growth in population.

Growth = 155 million * 0.01

Growth = 1.55 million

 

Since there are 12 months in a year, therefore the new jobs every month should be:

new jobs per month = 1.55 million / 12

<span>new jobs per month = 0.129 million = 129,167 </span>

8 0
4 years ago
Beats: A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a soun
e-lub [12.9K]

Answer:

The frequency of the beats is 43.6408 kHz

Explanation:

Given:

f = frequency = 39.6 kHz

vc = speed of the car = 35 m/s

vs = speed of the sound = 343 m/s

Question: What is the frequency of the beats, f' = ?

As the car moves towards the source, the frequency of the beats

f'=f*(1+\frac{v_{c} }{v_{s} } )=39.6*(1+\frac{35}{343} )=43.6408kHz

4 0
3 years ago
A ball of mass 0.15 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. b)
Art [367]

Answer:

Explanation:

If v be the velocity just after the rebound

Kinetic energy will be converted into potential energy

1/2 m v² = mgh

v² = 2gh

v = √ 2gh

= √ 2 x 9.8 x .96

= 4.33 m / s

4 0
3 years ago
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