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3 years ago

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Given that an atom of a semiconductor has a diameter of 2.18 å , what is the maximum number of moles that fit in the channel of

a processor chip that is 63.6 nm long, 74.2 nm , wide and 275 nm thick? assume that the atoms stack in a simple cubic arrangement.

1 answer:

andrezito [222]3 years ago

7 0

<span>Convert angstroms to nm for atom diameter 2.18/10=.218 nm. Divide diameter by length width and height. 63.6/.218=292 74.2/.218=327 275/.218=1261 Multiply these to get volume of atoms 120,037,500 Convert atoms to moles using Avogadro number 120,037,500/6.02*10^23=2*10^-16 moles</span>

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Solution:

Let the slope of the best fit line be represented by ' $m_{best}$ '

and the slope of the worst fit line be represented by ' $m_{worst}$ '

Given that:

$m_{best}$ = 1.35 m/s

$m_{worst}$ = 1.29 m/s

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Substituting values in eqn (1), we get

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2 years ago

4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of

Vesnalui [34]

Answer:

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Explanation:

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Pitch (P) = 5 teeth/in

Pressure angle ( $\Phi$ ) = 20°

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Power (H) = 30 hp

Teeth on gear ( $N_G$ ) = 50

Teeth on pinion ( $N_p$ ) = 20

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Let us first determine the diameter (d) of the pinion.

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For cut or milled profile; the velocity factor $(K_v)$ can be determined as follows:

$K_v = \frac{2000+V}{2000}$

$K_v = \frac{2000+2094.40}{2000}$

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However, there is need to get the value of the tangential load $(W^t)$ , in order to achieve that, we have the following expression

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$\sigma = \frac{K_vW^tp}{FY}$

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2 years ago

Read 2 more answers

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Answer:

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<em>b) 3.56 x 10^22 N</em>

<em></em>

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m is the mass of the Earth

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R is the distance between the sun and the Earth.

Substituting values, we have

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