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DIA [1.3K]
3 years ago
15

Calculate the average velocity of nitogen molecule at STP​

Chemistry
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

Nitrogen molecule is 28 neuclons×1.67×10-27 kg/nucleon = 4.68 д 10-26 kg. So the average speed of a gas molecule is about 500 m/sec. This is roughly the speed of sound in a gas 340 m/sec. So the average kinetic energy of the gas molecules is related to the temperature of the gas.

I hope this is helpful

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How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --> (NH4)2SO4
BartSMP [9]

Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

7 0
3 years ago
How is geothermal produced
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The steam rotates a turbine that activates a generator, which produces electricity. Many power plants still use fossil fuels to boil water for steam. Geothermal power plants, however, use steam produced from reservoirs of hot water found a couple of miles or more below the Earth's surface.
4 0
3 years ago
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How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lo
riadik2000 [5.3K]

Answer : The energy removed must be, -67.7 kJ

Solution :

The process involved in this problem are :

(1):C_6H_6(g)(425.0K)\rightarrow C_6H_6(g)(353.0K)\\\\(2):C_6H_6(g)(353.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(3):C_6H_6(l)(353.0K)\rightarrow C_6H_6(l)(335.0K)

The expression used will be:

\Delta H=[m\times c_{p,g}\times (T_{final}-T_{initial})]+m\times \Delta H_{vap}+[m\times c_{p,l}\times (T_{final}-T_{initial})]

where,

\Delta H = heat released by the reaction = ?

m = mass of benzene = 125 g

c_{p,g} = specific heat of gaseous benzene = 1.06J/g^oC

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC

\Delta H_{vap} = enthalpy change for vaporization = 33.9kJ/mole=33900J/mole=\frac{33900J/mole}{78.11g/mole}J/g=434.0J/g

Molar mass of benzene = 78.11 g/mole

Now put all the given values in the above expression, we get:

\Delta H=[125g\times 1.06J/g.K\times (353.0-(425.0))K]+125g\times -434.0J/g+[125g\times 1.73J/g.K\times (335.0-353.0)K]

\Delta H=-67682.5J=-67.7kJ

Therefore, the energy removed must be, -67.7 kJ

4 0
3 years ago
If the mass of reactants equals 100g, then the mass of the products would be equal to_______?
ioda
The answer would be A, 100g since it’s equal
7 0
1 year ago
Read 2 more answers
Help please
Mekhanik [1.2K]

Answer:

it's the regolith

hope this helps you

C Horizon - Also called regolith: the layer beneath the B Horizon and above the R Horizon. It consists of slightly broken-up bedrock. Plant roots do not penetrate into this layer; very little organic material is found in this layer. R Horizon - The unweathered rock (bedrock) layer that is beneath all the other layers.

7 0
3 years ago
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