Sorry but i can not decide i think it is B or C
Answer:
V = 27.98 L
Explanation:
Given data:
Mass of CO₂ = 33.0 g
Pressure = 500 torr
Temperature = 27°C
Volume occupied = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 33.0 g/ 44 g/mol
Number of moles = 0.75 mol
Volume of CO₂:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
Now we will convert the temperature.
27+273 = 300 K
Pressure = 500 /760 = 0.66 atm
By putting values,
0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K × 300 K
V = 18.47 atm.L/0.66 atm
V = 27.98 L
If it is a big open wound you apply pressure
5.7 g of KCl is produced.
<u>Explanation:</u>
First we have to write the balanced equation as,
Then we have to find the moles of potassium chlorate as,
Then we have to find the moles of KCl as,
From the moles of KCl, we have to find the mass using its molar mass by multiplying them as,
