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densk [106]
3 years ago
11

If one of the reactants in a reaction is Na2O, what is known about the products?

Chemistry
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

The products will have at least 2 Na atoms and 1 O atom.

Explanation:

const2013 [10]3 years ago
4 0

D. The products will have at least 2 Na atoms and 1 O atom.

<h3>Further explanation</h3>

If we refer to the law of mass conservation, which states that

<em>In a closed system, the masses before and after the reaction are the same </em>

then the number of atoms in the reactance will be the same as the number of atoms in the product

In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O

Like an example of this Na₂O reaction:

Na₂O + H₂O ⇒ 2 NaOH

Na : left =2, right = 2

O : left=2, right = 2

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Ill give u brainliest and all my points! pls help
dexar [7]

http://www.atnf.csiro.au/outreach/education/senior/cosmicengine/stars_hrdiagram.html. This will give u the answer, just go to link

6 0
3 years ago
I have to do this for homework please help :)
kramer

Answer:

1..... nucleus

2......electron cloud

3.......protons

4........Neutrons

5..........electron

6............electrons

7...............Isotopes

8.....,...........ions

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6 0
3 years ago
Identify any solutes and solvents present in a mixture of 0.05 mol ethanol, 1 liter water, and 0.2 g hydrogen
Varvara68 [4.7K]

Answer:

Water is the solvent

Both the ethanol and the hydrogen peroxide are the solute

Explanation:

Both the hydrogen peroxide and ethanol are sisobable in water.

There are 0.05 moles of ethanol.

1 litreof water contains 55.55 moles of water.

0.2 g of hydrogen peroxide contains 0.2/34 = 0.0059 moles of hydrogen peroxide (the 34 is the molar mass of hydrogen peroxide).

Since there are more moles of water, water becomes the solvent and the other two liquids dissolve in it.

6 0
3 years ago
A lead ball is added to a graduated cylinder containing 50.6 ml of water, causing the level of the water to increase to 93.0 mL.
Kamila [148]

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

<h3>What is a graduated cylinder?</h3>

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

93.0 mL= V_(lead ball) +50.6 ml

V_(lead ball) = 93.0 mL - 50.6 ml

V_(lead ball) = 42.4 ml

Hence, 42.4 ml is the volume in milliliters of the lead ball.

Learn more about the graduated cylinder  here:

brainly.com/question/13386106

#SPJ1

4 0
2 years ago
Balance the equation and write the reaction-quotient expression, qc. u(s) + f2(g) ----&gt; uf6(g)
Alona [7]
The equation presented above is that of uranium reacting with fluorine forming uranium fluoride. 

The chemical reaction can be balanced by carefully studying the equation and balancing the number of atoms of each of the element in both sides of the chemical reaction. That is,
 
                  <em>         U(s) + 3F₂(g) --> UF₆(g)</em>
4 0
3 years ago
Read 2 more answers
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