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natita [175]
3 years ago
14

What are some applications of Kepler’s laws still in use today?

Physics
2 answers:
Levart [38]3 years ago
7 0
<span>to plot and time the positions of comets and asteroids as they orbit the The application to Kepler's law are:
1. Sunplotting a course out of the solar system to explore other planets similar to Earth
2. plot the orbit of moons or man-made space satellites
</span><span>
An example of this is Kepler’s harmonic law is the third law of the Planetary Motion. He discovered this after ten years that there is a relation between the time of a planet’s orbit and its distance from the sun. The harmonic law states that the squares of the orbital periods of the planets around the Sun are proportional to the cubes of the planet’s orbital period</span>
tia_tia [17]3 years ago
7 0

Answer:

A. To plot and time the positions of comets and asteroids  

Explanation:

Kepler's law helps to understand the orbits of many planets and celestial bodies including comets and asteroids.

It was found that like other bodies or planets, comets also revolve around the sun in an elliptical path.

Consider sun is situated at one foci, when comets revolve around the sun the distance is very large but as soon as it comes closer to sun, it starts to melt thus forming a comet tail.

Hence time and position of a comet is described by Kepler's law.

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What is the frequency of ultraviolet light?
Triss [41]
Ultraviolet (UV) light is electromagnetic radiation with a wavelength shorter than that of visible light, but longer than X-rays, that is, in the range 10 nm to <span>400 nm</span>
7 0
3 years ago
A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension withou
Lemur [1.5K]

Answer: The answer is 13.02 meter

Explanation: your question is incomplete, the complete question is this if A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. One type of steel has a density of

7750kg/m3 and will break if the tensile stress exceeds 7.0×108N/m2.

You want to make a guitar string from a mass of 4.5 g of this type of steel. In use, the guitar string must be able to withstand a tension of 900 N without breaking. Your job is the following.

(a) Determine the maximum length the string can have

Answer:

As we know that density(p)= mass(m)/volume(V)

Solve for volume(V)= mass/density

If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg

And if density is in kg/m^3

Then volume will be V= 0.0037/7730 =>

4.79^10-7m^3

Now we know that stress = Force/Area

For Area = force/stress => 900/7*10^8=> 2795.95m^2

For length= volume/Area => 4.79^10-7/2795.95

Length= 13.02 m

4 0
3 years ago
A boy wants use his slingshot to shoot a water balloon into the air. His
Marrrta [24]

Answer:

A. 70 m OS the correct one

5 0
3 years ago
The kinetic theory states that the higher the temperature, the faster the
max2010maxim [7]

Answer: the higher the kinetic energy

Explanation:

4 0
3 years ago
3. What exerts a greater force on the table of 2 kg book lying flat or a 2 kg book on its
Darina [25.2K]

Answer:

A book on its side exerts a greater force.

Explanation:

Pressure = Force / Area

Assuming that 1kg = 10N

2kg = 20N

Area of book lying flat = 0.3m × 0.2m

                                     = 0.6m²

Pressure of book lying flat = 20N / 0.6m²

                                            = 30Pa (1 s.f.)

Area of book on its side = 0.2m × 0.05m

                                        = 0.01m²

Pressure of book on its side = 20N / 0.01m²

                                               = 2000Pa (1 s.f.)

Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.

5 0
2 years ago
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