Answer: D - The electron will move in a counterclockwise circular path if viewed in the direction of the magnetic field.
Explanation:
When the electron enters the field at an angle to the field direction the resulting path of the electron will be helical. Such motion occurs above the poles of the Earth where charges particles from the Sun spiral through the Earth's field to produce the aurorae.
Magnetic force on an electron = BILsinØ = B[e/t][vt] = BevØ
where v is the electron velocity
In a magnetic field the force is always at right angles to the motion of the electron (Fleming's left hand rule) and so the resulting path of the electron is circular.
Answer:
If the acceleration of an object remains constant, then its velocity is constant. False
If the acceleration of an object moving along a line is always 0, then its velocity is constant. True
It is impossible for the instantaneous velocity at all times aless than or equalstless than or equalsb to equal the average velocity over the interval aless than or equalstless than or equalsb. True
A moving object can have negative acceleration and increasing speed. False
Explanation:
First of all, before we can talk of acceleration, then there must be a change in velocity. If the velocity of a body is constant, then there will not be any acceleration at all.
If the acceleration is zero, then there is no change in velocity, the velocity is constant.
The instantaneous velocity is always changing all through the motion hence it cannot be determined at all times to equal the average velocity.
If the acceleration is negative, it simply means that the velocity is decreasing with time. Hence there can't be a negative acceleration and increasing velocity.
Answer:
V = (Vx^2 + Vy^2)^1/2 = (40^2 + 62^2)^1/2
V = 73.8 m/s
tan theta = Vy / Vx = 62/40 = 1.55
theta = 57.2 deg
Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;
where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N
186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²
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