Answer:
Magnesium also reacts with nitrogen in the air to produce some magnesium nitride (Mg3N2). Safety: Do not look directly at the burning magnesium due to the intensity of the light. A dry-powder fire extinguisher should be available. Disposal: Once cooled the solid magnesium products can be thrown in the trash.
Explanation:
Explanation:
Unlike the traditional definition of defining acid as any substance that can react with a base to form salt and water, there are two other definition of acid.
These are lewis acid and bronsted lowry acid.
Lewis acid is any substance that can accept a pair of non bonding electrons. This is why H+ is able to as a lewis acid.
Bronsted lowry definition on the other hand is as follows; A brosted lowry acid is any species that can donate a proton to another molecule. A bronsted lowry base is any specie that can accept a proton from another molecule. NH3 is able to accept a proton, hence it is termed as a bronsted lowry base.
BF3 act as a lewis acid because it can accept accept a pair of non bonding electrons. Generally; an atom, ion, or molecule with an incomplete octet of electrons can act as an Lewis acid.
Answer:
It would be 3 times as much gravity or 7 times
Explanation:
Closer=Burn
Farther=Freeze
We are the perfect distance away from the sun for it to sustain life.
Answer:
Approximately 75%.
Explanation:
Look up the relative atomic mass of Ca on a modern periodic table:
There are one mole of Ca atoms in each mole of CaCO₃ formula unit.
- The mass of one mole of CaCO₃ is the same as the molar mass of this compound:
. - The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element:
.
Calculate the mass ratio of Ca in a pure sample of CaCO₃:
.
Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be 
of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio 
:
.
In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:
.
