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3 years ago

Plz help ASAP Dhdhdg

Chemistry

1 answer:

Alborosie3 years ago

5 0

Answer:

They have the same number of Valence electrons

Explanation:

Hello?

The valence electrons are the one responsible for chemical reaction. Valence electrons are the electrons found/located on the outermost energy level.

I hope this helps. Have a nice studies

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A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

V₂ = 45.0 L

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

4 years ago

The volume of a gas is 1.15 L at STP. At what temperature would the volume of the gas increase to 1.56 L, if the pressure is dec

denis23 [38]

A gas occupies 1.15 L at standard pressure and temperature and 1.56 L at 317 K and 650 mmHg, assuming ideal behavior.

<h3>What is an ideal gas?</h3>

An ideal gas is a gas whose behavior can be explained through ideal gas laws. One of them is the combined gas law.

A gas occupies 1.15 L (V₁) at STP (T₁ = 273,15 K and P₁ = 760 mmHg). We can calculate the temperature (T₂) at which V₂ = 1.56 L and P₂ = 650 mmHg, using the combined gas law.

$\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2}\\T_2 = \frac{P_2 \times V_2 \times T_1}{P_1 \times V_1} = \frac{650mmHg \times 1.56 L \times 273.15K}{760mmHg \times 1.15 L} = 317 K$

A gas occupies 1.15 L at standard pressure and temperature and 1.56 L at 317 K and 650 mmHg, assuming ideal behavior.

Learn more about ideal gases here: brainly.com/question/15634266

#SPJ1

7 0

2 years ago

The water-gas shift reaction CO(g)+H2O(g)⇌CO2(g)+H2(g) is used industrially to produce hydrogen. The reaction enthalpy is ΔH∘=−4

Pani-rosa [81]

Answer:

The answers are in the explanation

Explanation:

A. For the reaction:

CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g); ΔH°=−41kJ.

As the reaction is exothermic ( ΔH°<0), you need to use low temperature to increase the equilibrium yield of hydrogen -LeChatelier's principle-.

We would use low temperature. For an exothermic reaction such as this, decreasing temperature increases the value of K and the amount of products at equilibrium.

c. No. We cannot increase the equilibrium yield of hydrogen by controlling the pressure of this reaction.

It is possible to increase the equilibrium yield of reaction by controlling the amount of reactants added. As reactants and products are gases, the pressure of the reaction will not change the amount of reactants or products in the equilibrium.

I hope it helps!

8 0

3 years ago

Weathering,erosion,pressing and cementing form what type of rock?

wlad13 [49]

Sedimentary Rock because weathering and erosion breaks down the rock. Then, while the rock is being pressed and cemented, its forms sediments.

6 0

3 years ago

Draw the Lewis structure for the sulfur dioxide molecule. Be sure to include all resonance structures that satisfy the octet rul

trapecia [35]

Answer:

See explanation

Explanation:

We have to remember that the formula of sulfur dioxide is $SO_2$ . So, the "S" atom is the central one and the "O" atoms are in the left and right of S. Additionally, "S" and "O" atom has 6 valence electrons each. With this in mind, we can start with a structure in which the left oxygen has 2 lone pairs and a double bond, the S atom can have a double bond a single bond and a lone pair and the right oxygen with 3 lone pairs with a single bond (structure A). Now, if we move the negative charge in the right (resonance) to the middle and the double bond to the left oxygen we will obtain structure B. Finally, we can move the negative charge in the left to the middle and we will obtain structure C. (See figure 1).

7 0

3 years ago