Answer:
The value is
Explanation:
From the question we are told that
The volume is
The initial pressure is ![P_1 = 1.01105 \ Pa](https://tex.z-dn.net/?f=P_1%20%3D%20%201.01105%20%5C%20%20Pa)
The initial temperature is ![T_1 = 3.00*10^2 \ K](https://tex.z-dn.net/?f=T_1%20%3D%203.00%2A10%5E2%20%5C%20%20K)
The final temperature is ![T_2 = 489 \ K](https://tex.z-dn.net/?f=T_2%20%3D%20%20489%20%5C%20%20K)
Generally for an adiabatic process the workdone is mathematically represented as
![W = - \Delta U](https://tex.z-dn.net/?f=W%20%3D%20-%20%20%5CDelta%20U)
Here
is the internal energy of the system which is mathematically represented as
![\Delta U = \frac{3}{2} * nR \Delta T](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20%2A%20%20nR%20%5CDelta%20T)
So
![W = - \frac{3}{2} * nR \Delta T](https://tex.z-dn.net/?f=W%20%3D%20-%20%20%20%5Cfrac%7B3%7D%7B2%7D%20%2A%20%20nR%20%5CDelta%20T)
Generally from ideal gas equation we have that
Here R is the gas constant with value ![R = 8.314 J/mol\cdot K](https://tex.z-dn.net/?f=R%20%20%3D%20%208.314%20J%2Fmol%5Ccdot%20K)
So
=> ![n = 0.009313 \ mol](https://tex.z-dn.net/?f=n%20%3D%200.009313%20%5C%20%20mol)
So
=>
Answer:
<u><em>2.</em></u>
<u><em>Oxygen in your alveoli is diffused in to your blood and Carbon Dioxide is taken out of the blood and into the lungs</em></u>
Explanation:
Hope this helps:)
I’m going to go with c. Mass and weight hope this helps
Answer:
<u><em>Example A, the object is moving in the positive direction (i.e., has a positive velocity) and is speeding up. When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration.</em></u>
<u><em></em></u>
The car undergoes an acceleration <em>a</em> such that
(45.0 km/h)² - 0² = 2 <em>a</em> (90 m)
90 m = 0.09 km, so
(45.0 km/h)² - 0² = 2 <em>a</em> (0.09 km)
Solve for <em>a</em> :
<em>a</em> = (45.0 km/h)² / (2 (0.09 km)) = 11,250 km/h²
Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em>, so that
<em>F</em> = (4500 kg) (11,250 km/h²)
Recall that Newtons (N) are measured as
1 N = 1 kg • m/s²
so we should convert everything accordingly:
11,250 km/h² = (11,250 km/h²) (1000 m/km) (1/3600 h/s)² ≈ 0.868 m/s²
Then the force is
<em>F</em> = (4500 kg) (0.868 m/s²) = 3906.25 N ≈ 3900 N