10 x 4^2 = 160 / 8..
V = 20m/s...
...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.
This is my guess since the problem says 4m/s^2
V= distance/ ST (traveled/used)
The work you put into something is the energy it has afterward (neglecting friction and other so-called non-conservative forces). This is called the work-energy theorem. Think of objects in a gravitational field as "energy piggy banks". If you put X joules of energy into it, that energy will be there as potential energy, stored for later. So if you do 144J of work to elevate the bucket from an initial position, what ever it is initially, the final gravitational energy is 144J greater than before.
The universal gravity formula is <span>F = G(Me)(Mm)/r^2. Lets use this formula to help us calculate what would happen if the Moon was twice as big.
</span><span>Mn = new mass = 2*Mm
</span><span>Fn = G(Me)(Mn)/r^2
</span><span>Fn = G(Me)(2Mm)/r^2
</span>Fn = 2*G(Me)(Mm)/r^2
<span>Fn = 2*F
</span>So 2 times the force it was before. The force should be the same, but you never know the moon and space as well know it can work in very mysterious ways.