Question

A step-up transformer has a primary coil with 100 loops and a secondary coil with 1,500 loops. If the primary coil is supplied with a household current of 120 V and 15 A, (a) what voltage is produced in the secondary circuit? (b) What current flows in the secondary circuit?

Answer 1

(a) The voltage that is produced in the secondary circuit is 1,800 V.

(b) The current that flows in the secondary circuit is 1 A.

Voltage in the secondary coil

Np/Ns = Vp/Vs

where;

• Np is number of turns in primary coil
• Ns is number of turns in secondary coil
• Vp is voltage in primary coil
• Vs is voltage in secondary coil

100/1500 = 120/Vs

Vs = (120 x 1500)/100

Vs = 1,800 V

Current in the secondary coil

Is/Ip = Vp/Vs

where;

• Is is secondary current
• Ip is primary current

Is = (IpVp)/Vs

Is = (15 x 120)/1800

Is = 1 A

Thus, the voltage that is produced in the secondary circuit is 1,800 V.

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