The simplified expression for the area of the rectangular table is Three-halves x squared, 3x²/2
<h3>What is the area of the rectangular table?</h3>
Since the carpenter built a square table with side length x. Next, he will build a rectangular table by tripling one side and halving the other.
To find the area of the rectangular table, we know that Area, A = LW where
Now, since the length of the square is x, and the rectangular table has one side of the square tripled and halving the other side .
So,
let
- length of the rectangular table = L = x/2 and
- width of rectangular = W = 3x
So, the area of the rectangular table A = LW
= x/2 × 3x
= 3x²/2
So, the simplified expression for the area of the rectangular table is Three-halves x squared, 3x²/2
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Answer:
Could you add the production of this soup if it was served in a restaurant?
Step-by-step explanation:
I'll answer then
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
I think that is is 8.3, but I could be incorrect!
Answer:
angle 2 is 55
Step-by-step explanation:
supposing angle 1 and 2 are supplementary angle
since angle 1 is 125
180-125=55
therefore angle 2 is 55
