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Ugo [173]
2 years ago
15

10. Anna wants to measure the water temperature in the pail. What instrument

Chemistry
1 answer:
Andre45 [30]2 years ago
5 0

Answer: A. Thermometer

Explanation:

A thermometer is used to measure temperature , while the others measure different things.

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At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of
Dvinal [7]

The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.031M/atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = 0.0905mol/L

Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

8 0
3 years ago
Please hurry and tell the answer to:
Flura [38]

Answer:

6.50 g of Hydrogen

Explanation:

We know that in every 20.0g of sucrose, there are 1.30g of hydrogen.

We now have 100.0g of sucrose. 100.0g is 5x larger than the 20.0g sample, which is a 5 : 1 ratio. Applying this ratio to the amount of hydrogen, we would have 5*1.3g of hydrogen in the 100.0g of sucrose.

5*1.3 = 6.5, so our answer is that there are 6.50g of hydrogen in 100.0g of sucrose.

Hope this helps!

5 0
1 year ago
How do I cook eggs? Please tell me
svetoff [14.1K]
You just throw them on the pan with the flame all the way up it will be done in a second !
3 0
3 years ago
Read 2 more answers
How many liters are present in 10 grams of H2O ?
Luba_88 [7]

Answer:

About 0.01

Explanation:

1 grams of H2O = 0.0010

0.0010 x 10 = 0.01

8 0
3 years ago
Which statement best describes an array of 10 elements where the elements are of a class type?
ladessa [460]
The array will be created with the elements equal to null.
3 0
3 years ago
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