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RSB [31]
3 years ago
10

2. A go-cart travels once around a circular track with a radius of 200m. What is its

Physics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

ggggggg

Explanation:

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A crate with a mass of m = 450 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate a
Zielflug [23.3K]

Answer:F_{v} =\mu_{k} mg

Magnitude of the force is 2601.9 N

Explanation:

m = 450 kg

coefficient of static friction μs = 0.73

coefficient of kinetic friction is μk = 0.59

The force required to  start crate moving is F_{s} =\mu_{s} mg.

but once crate starts moving the force of friction is reduced  F_{v} =\mu_{k} mg.

Hence  to keep crate moving at constant velocity we have to reduce the  force pushing crate ie F_{v} =\mu_{k} mg.

Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as  forces are balanced.

Magnitude of the force

F_{v} =\mu_{k} mg\\F_{v} =0.59 \times 450 \times 9.8\\F_{v} =2601.9  N

4 0
4 years ago
Answer it asap<br> I promise i will mark them the Brainly
nataly862011 [7]

Answer:

A) The acceleration is zero

<em>B) The total distance is 112 m</em>

Explanation:

<u>Velocity vs Time Graph</u>

It shows the behavior of the velocity as time increases. If the velocity increases, then the acceleration is positive, if the velocity decreases, the acceleration is negative, and if the velocity is constant, then the acceleration is zero.

The graph shows a horizontal line between points A and B. It means the velocity didn't change in that interval. Thus the acceleration in that zone is zero.

A. To calculate the acceleration, we use the formula:

\displaystyle a=\frac{v_2-v_1}{t_2-t_1}

Let's pick the extremes of the region AB: (0,8) and (12,8). The acceleration is:

\displaystyle a=\frac{8-8}{12-0}=0

This confirms the previous conclusion.

B. The distance covered by the body can be calculated as the area behind the graph. Since the velocity behaves differently after t=12 s, we'll split the total area into a rectangle and a triangle.

Area of rectangle= base*height=12 s * 8 m/s = 96 m

Area of triangle= base*height/2 = 4 s * 8 m/s /2= 16 m

The total distance is: 96 m + 16 m = 112 m

4 0
3 years ago
) A steel guitar string with a diameter of 1.00 mm is stretched between supports 80.0 cm apart. The temperature is 0.0°C. (a) Fi
ladessa [460]

Answer: a. Mass per unit length =0.0245kg/m

b. Tension =2.45x10^-8N

C. Tension = 2.45 x10^-8N

Fundamental frequency =200Hz

Explanation:

7 0
4 years ago
(AKS 1c) A bowler rolls a bowling ball with a speed of 4 m/s. It took 2s to reach the pins at the end of the lane. What is the f
Advocard [28]

Answer:

B is the answer

Explanation:

When A is divided by 7x, it multiplies to0.81

6 0
3 years ago
star a and star b have measured stellar parallax of 0.58 arc second and 0.73 arc second, respectively. which star is closer?
goldenfox [79]

Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.

<h3>What is stellar parallax and distance measurement using stellar parallax?</h3>

To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.

A straightforward correlation exists between the distance of a star and parallax angle:

d=\frac{1}{p}

The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.

Stellar parallax of star A= 0.58 arcseconds

Stellar parallax of star B= 0.73 arcseconds

So, on applying the formula,

The distance of the star A= 1.72pc

And the distance of the star B= 1.36pc

Therefore, star B is closer than star A.

To know more about stellar parallax, visit:

brainly.com/question/29352944

#SPJ4

3 0
1 year ago
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