About 40 000 km/h
Here you go:
Here you go:
An electrical motor spins at a constant 2662.0 rpm. If the armature radius is 6.725 cm, what is the acceleration of the edge of
1 answer:
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Answer:
The value is
Explanation:
From the question we are told that
The wavelength is
The velocity is
The mass of electron is
Generally the energy of the incident light is mathematically represented as
Here c is the speed of light with value
h is the Planck constant with value
So
=>
Generally the kinetic energy is mathematically represented as
=>
=>
Generally the ionization energy is mathematically represented as
=>
Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is , and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
