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Semenov [28]
3 years ago
9

KCI is a molecule. True or False

Chemistry
2 answers:
dimaraw [331]3 years ago
7 0
The answer is true the first one
Monica [59]3 years ago
4 0

Answer: duh

Explanation:

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As the balloon rises what happens to the external pressure
nevsk [136]

Answer:

As the ballon rises higher the atmospheric pressure will drop if the ballon is made of an elastic material,it will stretch to allow the gas inside it to expand

7 0
3 years ago
Is the answer less dense?
xxMikexx [17]
I believe it is less dense.. that is why ice floats on water
5 0
4 years ago
How are the codes (chemical formulas) for pure substances different from those for mixtures?
Gnesinka [82]

Answer : The chemical formula of pure substances are different from those of mixtures because all the matter that exists on earth can be classified into two categories namely; pure substances and mixtures.

A pure substance always consists of a single element or compound. Example Oxygen is formed only of oxygen (O) atoms; whereas the table salt which is formed only by sodium chloride (NaCl) molecules is a compound which is made up of pure elements. A pure substance cannot be further divided into its components.

A mixture is made up of different compounds and/or elements. It can be easily separated using any physical method. Example, sand, salt and saw dust mixed together as a mixture. Also, it will not have a definite chemical formula.

Please refer the attachment for better understanding.

5 0
3 years ago
Assume that 50.0mL 50.0mL of 1.0MNaCl(aq) 1.0MNaCl(aq) and 50.0mL 50.0mL of 1.0M AgNO 3 (aq) 1.0MAgNO3(aq) were combined. Accord
S_A_V [24]

Answer:

The amount of precipitate formed would 7.175 grams of silver chloride.

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of NaCl = n

Volume of NaCl solution = 50.0 mL = 0.050 L

Molarity of the hydrogen peroxide = 2.0 M

n=2.0 M\times 0.050 L=0.100 mol

Moles of silver nitarte = n'

Volume of silver  nitrate solution = 50.0 mL = 0.050 L

Molarity of the silver nitrate = 1.0 M

n'=1.0 M\times 0.050 L=0.050 mol

NaCl(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NaNO_3(aq)

According to reaction, 1 mole of of silver nitrate reacts with 1 mole of NaCl. Then 0.050 mole of silve nitrate will :

\frac{1}{1}\times 0.050 mol=0.050 mol of NaCl

This means that silver nitrate is in limiting amount and NaCl is in excessive amount.

So, the amount of AgCl depends upon amount of silver nitrate.

According to reaction, 1 mole of silver nitrate gives 1 mole of AgCl.

Then 0.050 moles of silver nitrate will give;

\frac{1}{1}\times 0.050 mol=0.050 mol of AgCl

Mass of 0.050 moles of AgCl ;

0.050 mol\times 143.5 g/mol=7.175 g

The amount of precipitate formed would 7.175 grams of silver chloride.

8 0
3 years ago
What is the new freezing point for a 0.811m solution of Li2O in water?
rewona [7]

Answer:

Freezing T° of solution = - 4.52°C

Explanation:

ΔT = Kf . m . i

That's the formula for colligative property about freezing point depression.

Li₂O is an oxide that can not be dissociated but, if we see it's a ionic compound.

Li₂O →  2Li⁺  +  O⁻²

3 moles of ions have been formed. Ions dissolved in solution are i, what we call Van't Hoff factor.

m is molality → 0.811 m, this is data

Kf →Cryoscopic constant, for water is 1.86 °C/m

and ΔT = Freezing T° of pure solvent - Freezing T° of solution

We replace: 0°C - Freezing T° of solution = 1.86°C/m . 0.811 m . 3

Freezing T° of solution = - 4.52°C

3 0
3 years ago
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