Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
Answer:
Step-by-step explanation:
x1 = 0.5 x2 = -0.4 y1 = 1.3 y2 = -1.3
=2.75
Answer:
its option 4
Step-by-step explanation:
Answer:
(1, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 3
y = -3x + 6
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 3 = -3x + 6
- [Subtraction Property of Equality] Subtract 6 on both sides: -3 = -3x
- [Division Property of Equality] Divide -3 on both sides: 1 = x
- Rewrite/Rearrange: x = 1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3(1) + 6
- Multiply: y = -3 + 6
- Add: y = 3
