<h3>
Answer:</h3>
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
<h3>
Explanation:</h3>
- The equation for the reaction shown represents the combustion of ethane.
C₂H₆ + O₂ → CO₂ + H₂O
- To balance the equation we put the coefficients, 2, 7, 4, and 6 on the reactants and products.
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
- Balancing chemical equations makes the number of atoms of each element equal on both side of the equation.
- It ensures that chemical equations obey the law of conservation of mass in chemical reactions.
Solution:
At the equivalence point, moles NaOH = moles benzoic acid
HA + NaOH ==> NaA + H2O where HA is benzoic acid
At the equivalence point, all the benzoic acid ==> sodium benzoate
A^- + H2O ==> HA + OH- (again, A^- is the benzoate anion and HA is the weak acid benzoic acid)
Kb for benzoate = 1x10^-14/4.5x10^-4 = 2.22x10^-11
Kb = 2.22x10^-11 = [HA][OH-][A^-] = (x)(x)/0.150
x^2 = 3.33x10^-12
x = 1.8x10^-6 = [OH-]
pOH = -log [OH-] = 5.74
pH = 14 - pOH = 8.26
There are a total of four quantum numbers that govern the
electrons. These are the principal quantum number (n), the angular quantum
number (l), the magnetic quantum number (ml) and lastly the spin quantum number
(ms). Each electron has a unit set of the four quantum numbers.
Since the first 3 quantum numbers is already specified, so
the remaining to be filled is the ms quantum number which can only have values
of +1/2 and -1/2. So we have 2 electrons.
Answer:
<span>2 electrons</span>
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
It is one of the most common types of chemical reactions and can also be called a synthesis reaction. In this reaction, two or more chemical species combine to form a more complex product.
