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2 years ago

How do we know that sunspots are associated with the sun's magnetic field?

Chemistry

1 answer:

Genrish500 [490]2 years ago

8 0

Answer:

astronomers know that sunspots are associated with magnetic fields because they can look at the spectral lines that come from the sunspots and measure by how much these lines are split.

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The mass of a piece of iron is 39 g and its volume is 5 cm. What is its

klio [65]

Answer:

Explanation:

Divide the mass by the volume.

3 0

3 years ago

Empirical formula of 25.13g sulfur and 49.87g copper

antiseptic1488 [7]

Copper + sulfur create copper sulfide.

It's a lengthy process to find the empirical formula:

Sulfur:

$25.13g * \frac{1 mol}{32.065 g} = 0.78 mol$

Copper:

$49.87 * \frac{1 mol}{63.546 g} = 0.78mol$

S:Cu => $\frac{0.78}{0.78} :\frac{0.78}{0.78}$ => $(1:1) * 1$ => $1:1$

The empirical formula would just be $CuS$

7 0

3 years ago

Water and salt are compounds made of the combination of more than one type of atom. Which statement is false?

Whitepunk [10]

D
explanation
slattttt

7 0

3 years ago

Use the graph to calculate the instantaneous rate of formation of HBr at 50 s

Lina20 [59]

<u>Answer:</u> The instantaneous rate of formation of HBr at 50 s is $1.4\times 10^{-2}M/s$

<u>Explanation:</u>

From the graph,

Initial rate of the $Br_2$ = 1.0 M

Time when the concentration of $Br_2$ is 0.5 M (half the concentration ) = 60 sec

For first order reaction:

Calculating rate constant for first order reaction using half life:

$t_{1/2}=\frac{0.693}{k}$ .....(1)

$t_{1/2}$ = half life period = 60 s

k = rate constant = ?

Putting values in equation 1:

$k=\frac{0.693}{60s}\\\\k=0.01155s^{-1}$

For the given chemical reaction:

$H_2(g)+Br_2(g)\rightarrow 2HBr(g)$

Rate of the reaction = $-\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}$

Negative sign represents the disappearance of the reactants

From the above expression:

$k[Br_2]=-\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}$

At 50 seconds, $[Br_2]=0.6 M$

Plugging values in above expression, we get:

$\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}=0.01155\times 0.6\\\\\frac{\Delta [HBr]}{\Delta t}=2\times 0.01155\times 0.6=0.01386=1.4\times 10^{-2}M/s$

Hence, the instantaneous rate of formation of HBr at 50 s is $1.4\times 10^{-2}M/s$

6 0

3 years ago

What happens to the copper sulphate crystals when they are heated that causes them to change color?

mote1985 [20]

Answer:

Heating the CuSO4. 5H2O crystals causes then to loose the water of crystallisation that is the 5H2O part. It becomes anhydrous copper sulphate. Its colour changes to white from blue.

7 0

3 years ago