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2 years ago

How do we know that sunspots are associated with the sun's magnetic field?

Chemistry

1 answer:

Genrish500 [490]2 years ago

8 0

Answer:

astronomers know that sunspots are associated with magnetic fields because they can look at the spectral lines that come from the sunspots and measure by how much these lines are split.

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If I have 251.14 grams of citric acid and calcium bicarbonate mixture how much citrus acid do I have??

Snezhnost [94]

About 255.3 grams is the answer I believe. I just had a school work packet and had that question on it, and that is the answer that I had put on it I believe.

6 0

4 years ago

What are the three main parts of an atom and what are their charges?

Leviafan [203]

Answer:

Three main parts are Protons (pos charge) Neutrons (no charge) Electrons (negative charge) and the electron is found on the outside of the nucleus

Explanation:

8 0

3 years ago

There is a boy i like. i don't think he like me what do i do

SCORPION-xisa [38]

Answer:

tell em

Explanation:

7 0

3 years ago

Order the follow processes from (1) the least work done by the system to (5) the most work done by one mole of an ideal gas at 2

quester [9]

Answer : The order of process from (1) the least work done by the system to (5) the most work done by the system will be:

(1) < (5) < (3) < (4) < (2)

Explanation :

<u>The formula used for isothermally irreversible expansion is :</u>

$w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)$

where,

w = work done

$p_{ext}$ = external pressure

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

<u>The expression used for work done in reversible isothermal expansion will be,</u>

$w=-nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = ?

n = number of moles of gas = 1 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = $25^oC=273+25=298K$

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

First we have to determine the work done for the following process.

(1) An isothermal expansion from 1 L to 10 L at an external pressure of 2.5 atm.

$w=-p_{ext}(V_2-V_1)$

$w=-(2.5atm)\times (10-1)L$

$w=-22.5L.atm=-22.5\times 101.3J=-2279.25J$

(2) A free isothermal expansion from 1 L to 100 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{100L}{1L})$

$w=-11409.6J$

(3) A reversible isothermal expansion from 0.5 L to 4 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{4L}{0.5L})$

$w=-5151.97J$

(4) A reversible isothermal expansion from 0.5 L to 40 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{40L}{0.5L})$

$w=-10856.8J$

(5) An isothermal expansion from 1 L to 100 L at an external pressure of 0.5 atm.

$w=-p_{ext}(V_2-V_1)$

$w=-(0.5atm)\times (100-1)L$

$w=-49.5L.atm=-49.5\times 101.3J=-5014.35J$

Thus, the order of process from (1) the least work done by the system to (5) the most work done by the system will be:

(1) < (5) < (3) < (4) < (2)

8 0

3 years ago

Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat

Vilka [71]

Answer:

The root mean squared velocity for CF2Cl2 is $v_{rms}= 207.06 m/s$

Explanation:

From the question we are told that

The temperature is $T = -65 ^oC = -65+273 = 208K$

Root Mean Square velocity is mathematically represented as

$v _{rms} = \sqrt{\frac{3RT}{MW} }$

Where T is the temperature

MW is the molecular weight of gas

R is the gas constant with a value of $R = 8.314 JK^{-1} mol^{-1}$

For CF2Cl2 its molecular weight is 0.121 kg/mol

Substituting values

$v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }$

$v_{rms}= 207.06 m/s$

5 0

3 years ago

Read 2 more answers