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saw5 [17]
2 years ago
12

How do we know that sunspots are associated with the sun's magnetic field?

Chemistry
1 answer:
Genrish500 [490]2 years ago
8 0

Answer:

astronomers know that sunspots are associated with magnetic fields because they can look at the spectral lines that come from the sunspots and measure by how much these lines are split.

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How would this atomic structure change if you built an atom of Krypton which has an atomic number of 36?
jenyasd209 [6]

Answer:

Explanation:

d

5 0
3 years ago
Which of the following correctly represents the transmutation in which a curium-242 nucleus is bombarded with an alpha particle
Alekssandra [29.7K]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Transmutation is defined as the process in which one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of curium-242 nucleus with alpha particle (helium nucleus) follows:

_{96}^{242}\textrm{Cm}+_4^2\textrm{He}\rightarrow _{98}^{245}\textrm{Cf}+_0^1\textrm{n}

The product formed in the nuclear reaction are californium-245 nucleus and a neutron particle.

6 0
3 years ago
HELP ASAP ITS TIMED!!!
Tpy6a [65]

Answer:

C would be the right answer

5 0
3 years ago
Read 2 more answers
What happens when acetylene reacts with silver powder?​
horrorfan [7]
It dissolves I think I know I am expert and. Ute
6 0
3 years ago
he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

\Delta S=\frac{n*\Delta H}{T}

Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Best regards.

3 0
3 years ago
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