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S_A_V [24]
3 years ago
10

A prokaryotic cell does not have

Chemistry
1 answer:
krok68 [10]3 years ago
3 0

Answer:

D

Explanation:

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CalcuLate the velocity of an electron ejected if 300.0 mm of light is applied to the surface. A wavelength of 795 nm has suffici
worty [1.4K]
The equation relating velocity and wavelength is written below:

v = λf
where λ is the wavelength in m while f is frequency in 1/s.

Let's determine first the frequency from the speed of light:
c = distance/time, where c is the speed of light equal to 3×10⁸ m/s
3×10⁸ m/s = (300 mm)(1 m/1000 mm)/ time
time = 1×10⁻⁹ seconds
Since f = 1/t,
f = 1/1×10⁻⁹ seconds = 10⁹ s⁻¹

Thus,
v = (795×10⁻⁹ m)(10⁹ s⁻¹)
v = 795 m/s
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3 years ago
What is used to calculate volts
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A multiplication formula
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Read 2 more answers
If 0.255 moles of AgNO₃ react with 0.155 moles of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ co
Ber [7]

Answer: 6.162g of Ag2SO4 could be formed

Explanation:

Given;

0.255 moles of AgNO3

0.155 moles of H2SO4

Balanced equation will be given as;

2AgNO3(aq) + H2SO4(aq) -> Ag2SO4(s) + 2HNO3(aq)

Seeing that 2 moles of AgNO3 is required to react with 1 moles of H2SO4 to produce 1 mole of Ag2SO4,

Therefore the number of moles of Ag2SO4 produced is given by,

n(Ag2SO4) = 0.255 mol of AgNO3 ×

[0.155mol H2SO4 ÷ 2 mol AgNO3] x

[ 1 mol Ag2SO4 ÷ 1 mol H2SO4]

= 0.0198 mol of Ag2SO4.

mass = no of moles x molar mass

From literature, molar mass of Ag2SO4 = 311.799g/mol.

Thus,

Mass = 0.0198 x 311.799

= 6.162g

Therefore, 6.162g of Ag2SO4 could be formed

4 0
3 years ago
Complete the table below by filling in the principal quantum number n and angular momentum quantum number l for each electron su
Alja [10]

Answer:

For 4f  the principal quantum number, n is 4 and the angular momentum quantum number l is 3

7s: n = 7 and l = 0

4p: n = 4 and l = 1

7p: n = 7 and l = 1

Explanation:

The principal quantum number gives the energy level of the electron in an atom. It shows the shells in which an electron is in an atom.

if n = 1, 2, 3, 4...; it corresponds to K, L, M, N... shells in an atom

The numerical coefficient of the subshell gives the pricipal quantum number.

for instance in 4f, the principal quantum number, n is 4  because 4 is the coefficient.

The angular momentum quantum number, l gives the energy sublevel or subshell.

Angular momentum quantum number has integral values, l = 0, 1, 2, 3... which correspond to  s, p, d, f,..  orbitals.

Thus for 4f  the principal quantum number, n is 4 and the angular momentum quantum number l is 3

similarly, for 7s: n = 7 and l = 0

4p: n = 4 and l = 1

7p: n = 7 and l = 0

using similar approach for others

3 0
3 years ago
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