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HACTEHA [7]
3 years ago
8

Find the radius Rrigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

10^31 W and has a surface temperature of 11,000 K. Assume that the star is spherical.
Physics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

r = 1.61 x 10^{11} m

Explanation:

energy radiated (H) = 2.7 x 10^31 W

surface temperature (T)  = 11,000 k

assuming ε = 1 and taking σ = 5.67 x 10^{-8} W/m^{2}.K^{4}

we can find the radius of the star from the equation below

H = A x  ε x σ x T^{4}              

where area (A) = 4 x π x r^{2} (assuming it is a sphere)

therefore  the equation becomes

H = 4 x π x r^{2} x  ε x σ x T^{4}  

2.7 x 10^31  = 4 x π x r^{2} x  1 x 5.67 x 10^{-8}  x (11,000)^{4}

r = \sqrt{\frac{2.7 x 10^31}{4 x π x 1 x 5.67 x 10^{-8}  x (11,000)^{4}} }

r = 1.61 x 10^{11} m

       

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The voltage between two parallel plates separated by a distance of 3. 0 cm is 120 v. The electric field between the plates is?
Lapatulllka [165]

The electric field between plates is 4000V/m.

An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles.

The value of the electric field has dimensions of force per unit charge. In the metre-kilogram-second and SI systems, the appropriate units are newtons per coulomb, equivalent to volts per metre.

The voltage between points A and B is

V=E.d

E =V/d  (uniform E- field only)  

where  d is the distance from A to B, or the distance between the plates.

Given:

distance d = 3 cm

voltage V = 120 V

Electric field E = V/d

                     E = 120 V / 3cm

                     E = 40 V / 1 cm               [ 1 cm = 1/100 m ]

                    E = 4000 V/m.

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6 0
1 year ago
the object on the right gained mass so that it had as much mass as the object on the left, how would the gravitational force bet
kherson [118]

The gravitational force between the objects A. It would increase.

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m_1,m_2 are the masses of the two objects

r is the separation between the objects

In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of m_2 increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.

Therefore, the correct answer is

A. It would increase.

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6 0
3 years ago
Read 2 more answers
Find :
Pepsi [2]

Answer:

Explanation:

b) Gravity reduces the initial upward velocity to zero in a time of

t = v/g = 40/10 = 4 s

a) h =  v₀t + ½gt² = 40(4) +  ½(-10)4² = 80 m

or

v² = u² + 2as

h = (0² - 40²) / 2(-10) = 80 m

8 0
2 years ago
The mass of an object is determined by: weighing the object with a scale multiplying the height, width, and length measuring the
rosijanka [135]
The true scientific way is the last: using the water displacement method
7 0
3 years ago
A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is
frozen [14]

Answer:

60 kg m/s

Explanation:

Let a\;\; m/s^2 be the acceleration of the object.

As the acceleration of the object is constant, so

a=\frac {v-u}{t}\cdots(i)

Given that applied force, F=6.00 N,

From Newton's second law, we have

F= m\times a,

\Rightarrow F=\frac {m(v-u)}{t} [from equation (i)]

\Rightarrow Ft=m(v-u)

\Rightarrow Ft=mv-mu

\Rightarrow mv-mu=6\times 10 [given that time, t=10 s and F=6 N]

\Rightarrow mv-mu=60 kg \;m/s

Here mv is the final momentum of the object and mu is the initial momentum of the object.

So, the change in the momentum of the object is mv-mu.

Hence, the change in the momentum of the object is 60 kg m/s.

6 0
3 years ago
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