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HACTEHA [7]
3 years ago
8

Find the radius Rrigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

10^31 W and has a surface temperature of 11,000 K. Assume that the star is spherical.
Physics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

r = 1.61 x 10^{11} m

Explanation:

energy radiated (H) = 2.7 x 10^31 W

surface temperature (T)  = 11,000 k

assuming ε = 1 and taking σ = 5.67 x 10^{-8} W/m^{2}.K^{4}

we can find the radius of the star from the equation below

H = A x  ε x σ x T^{4}              

where area (A) = 4 x π x r^{2} (assuming it is a sphere)

therefore  the equation becomes

H = 4 x π x r^{2} x  ε x σ x T^{4}  

2.7 x 10^31  = 4 x π x r^{2} x  1 x 5.67 x 10^{-8}  x (11,000)^{4}

r = \sqrt{\frac{2.7 x 10^31}{4 x π x 1 x 5.67 x 10^{-8}  x (11,000)^{4}} }

r = 1.61 x 10^{11} m

       

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You work in a materials testing lab and your boss tells you to increase the temperature of a sample by 37.1 ∘c . the only thermo
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3 years ago
the difference between speed and velocity is that A) speed is a vector and requires a direction. B) speed is a vector and requir
jenyasd209 [6]

The correct answer is C. Velocity is a vector and requires a direction.

Explanation:

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Considering this, it can be concluded the difference between speed and velocity is that "velocity is a vector and requires a direction" because velocity includes both the distance and time (speed) along with the direction while speed focuses only on time and distance.

6 0
3 years ago
Read 2 more answers
Two parallel plates having charges of equal magnitude but opposite sign are separated by 29.0 cm. Each plate has a surface charg
wel

Answer:

(a) E = 3.6 x 10³ N/C = 3.6 KN/C

(b) ΔV = 1044 Volts

(c) K.E = 1.67 x 10⁻¹⁶ J

(d) Vf = 4.47 x 10⁵ m/s

(e) a = 3.45 x 10¹¹ m/s²

(f) F = 5.76 x 10⁻¹⁶ N

(g) E = 3.6 x 10³ N/C = 3.6 KN/C  

(h)  Both values are same in part (h) and (a)

Explanation:

(a)

Electric field between oppositely charged plates is given as follows:

E = σ/ε₀

where,

E = Electric Field Intensity = ?

σ = surface charge density = 32 nC/m² = 3.2 x 10⁻⁸ C/m²

ε₀ = Permittivity of free space = 8.85 x 10⁻¹² C²/N.m²

Therefore,

E = (3.2 x 10⁻⁸ C/m²)/(8.85 x 10⁻¹² C²/N.m²)

<u>E = 3.6 x 10³ N/C = 3.6 KN/C</u>

<u></u>

(b)

E = ΔV/r

ΔV = Er

where,

r = distance between plates = 29 cm = 0.29 m

ΔV = Potential Difference = ?

ΔV = (3.6 x 10³)(0.29)

<u>V = 1044 Volts</u>

<u></u>

(c)

Kinetic Energy of Proton = Work done on Proton

K.E = F r

but,  F = E q

K.E = E q r

where,

q = charge on proton = 1.6 x 10⁻¹⁹ C

Therefore,

K.E = (3600 N/C)(1.6 x 10⁻¹⁹ C)(0.29 m)

<u>K.E = 1.67 x 10⁻¹⁶ J</u>

<u></u>

(d)

K.E = (1/2)m(Vf² - Vi²)

where,

m = mass of proton = 1.67 x 10⁻²⁷ kg

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

Therefore,

1.67 x 10⁻¹⁶ J = (1/2)(1.67 x 10⁻²⁷ kg)(Vf² - (0 m/s)²]

Vf² = (1.67 x 10⁻¹⁶ J)(2)/(1.67 x 10⁻²⁷ kg)

Vf = √(20 x 10¹⁰ m²/s²)

<u>Vf = 4.47 x 10⁵ m/s</u>

<u></u>

(e)

2as = Vf² - Vi²

2(a)(0.29 m) = (4.47 x 10⁵ m/s)² - (0 m/s)²

a = (20 x 10¹⁰ m²/s²)/0.58 m

<u>a = 3.45 x 10¹¹ m/s²</u>

<u></u>

(f)

F = ma

F = (1.67 x 10⁻²⁷ kg)(3.45 x 10¹¹ m/s²)

<u>F = 5.76 x 10⁻¹⁶ N</u>

<u></u>

(g)

E = F/q

E = (5.76 x 10⁻¹⁶ N)/(1.6 x 10⁻¹⁹ C)

<u>E = 3.6 x 10³ N/C = 3.6 KN/C</u>

<u></u>

(h)

<u>Both values are same in part (h) and (a)</u>

7 0
3 years ago
Which of the following describes deposition?
alexgriva [62]

Deposition is geological process of sediments, soil and rocks that are added to land-form or land mass. Wind, ice, water, and gravity transport weathered surface material, which, at the loss of enough kinetic energy in the fluid, is deposited. Technically  Building up layers of sediment.

hope this helps

:D

7 0
3 years ago
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