Answer:
Option C. Objects 1 and 3 will not move, and objects 2 and 4 will accelerate
upward.
Explanation:
The following data were obtained from the question:
OBJECT >>>>>>>>> WEIGHT (N)
1 >>>>>>>>>>>>>>>> 35
2 >>>>>>>>>>>>>>>> 23
3 >>>>>>>>>>>>>>>> 26
4 >>>>>>>>>>>>>>>> 18
Force (F) applied = 25 N
From the above, the force applied to each object is 25N. Thus the following can be concluded based on the data given above:
For object 1:
Weight = 35 N
Force applied = 25 N
Thus, the object will not move since the weight of the object is greater than the force applied
For object 2:
Weight = 23 N
Force applied = 25 N
Thus, the object will move since the force applied is greater than the weight of the object.
For object 3:
Weight = 26 N
Force applied = 25 N
Thus, the object will not move since the weight of the object is greater than the force applied.
For object 4:
Weight = 18 N
Force applied = 25 N
Thus, the object will move since the force applied is greater than the weight of the object.
From the above illustrations, Object 1 and 3 will not move, and objects 2 and 4 will accelerate i.e move
Answer:
- the coating’s index of refraction is 1.25
- the required thickness is 104.1667 nm
Explanation:
Given the data in the question;
Thickness of coating t = 100 nm
wavelength λ = 500nm
we know that refractive index is;
t = λ/4n
make n, the subject of formula
t4n = λ
n = λ / 4t
we substitute
n = 500 / ( 4 × 100 )
n = 500 / 400
n = 1.25
Therefore, the coating’s index of refraction is 1.25
2)
given that;
Index of refraction of the coating; n = 1.20
λ = 500 nm
thickness of coating t = ?
t = λ / 4n
we substitute
t = 500 / ( 4 × 1.2 )
t = 500 / 4.8
t = 104.1667 nm
Therefore, the required thickness is 104.1667 nm
F=ma
a=(v2-v1)/(t2-t1)
a=(6-0)/(12-0)
a=6/12
a= .5 m/s^2
f=2300kg*.5m/s^2
f=1150N
f=1200N if using correct sig figs
Yes. Your answer is correct. I hope you do well on the quiz or whatever it is.
