Question

What is the PH of a 7.5x10^-3 M OH solution

Answer 1

Answer : The pH of a solution is, 11.88

Explanation:  Given,

Concentration of $OH^-$ ion = $7.5\times 10^{-3}M$

First we have to calculate the pOH.

Formula used :

$pOH=-\log [OH^-]$

$pOH=-\log (7.5\times 10^{-3})$

$pOH=2.12$

Now we have to calculate the pH.

Formula used :

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-2.12=11.88$

Therefore, the pH of a solution is, 11.88

Answer 2

pH: 11.8750612634
pOH: 2.12493873661
[H+]: 1.33333333333E-12
[OH-]: 0.0075
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