Answer : The formal charge on central Cl atom is -1.
Explanation :
The given molecule is, ![Cl^-_3](https://tex.z-dn.net/?f=Cl%5E-_3)
First we have to determine the total number of valence electrons in, ![Cl^-_3](https://tex.z-dn.net/?f=Cl%5E-_3)
As we know, chlorine has 7 valence electrons.
Total number of valence electrons in
= 3(7) + 1 = 22 electrons
Electrons used in bonding pair = 4
Electrons used as lone pair = 22 - 4 = 18
Now we have to calculate the formal charge on central Cl atom.
- Formal charge = Number of valence electrons of a central atom - (2 × Number of lone pairs) - Number of bond pairs
Formal charge on central Cl atom = 7 - (2 × 3) -2 = -1
Therefore, the formal charge on central Cl atom is -1.
The lewis-dot structure of
is shown below.
Answer:
1. kmol of methanol= 3.12 Kmol
2. kmol of water= 5.55 Kmol
3. Liters of methanol= 126.4 L
4. L of water= 100 L
Explanation:
1. kmol of methanol?
32.04 kg methanol ______________ 1 kmol of methanol
100 kg of methanol_______________ X= 3.12 kmol ofmethanol
2. kmol of water?
18.01 kg water ______________ 1 kmol of wáter
100 kg of wáter_______________ X= 5.55 kmol of water
3. Liters of methanol?
0.791 kg methanol _______________________1.00 L of methanol
100kg methanol _______________________x= 126.4 L of methanol
4. L of water?
1kg water _______________________1.00 L of water
100kg water _______________________x= 100 L of water
Answer:
See below
Explanation:
Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters
=> Grams of solute = Molarity x Vol in Liters x formula wt
= (0.250M)(0.750L)(212.3g/mol)
= 39.8 grams
Answer:
hydrogen gas and zinc sulphide
Refer to the diagram shown below.
The piston supports the same load W at both temperatures.
The ideal gas law is
![pV=nRT](https://tex.z-dn.net/?f=pV%3DnRT)
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant
State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter
State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter
Because V, n, and R remain the same between the two temperatures, therefore
![\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%20%5Cfrac%7Bp_%7B2%7D%7D%7BT_%7B2%7D%7D%20)
If the supported load is W kg, then
![p_{1} = \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} = 20.3718W \, Pa](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%20%20%5Cfrac%7BW%20%5C%2C%20N%7D%7B%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20d_%7B1%7D%5E%7B2%7D%7D%20%3D%20%5Cfrac%7B4W%20%5C%2C%20N%7D%7B%5Cpi%20%280.25%20%5C%2C%20m%29%5E%7B2%7D%7D%20%3D%20%2020.3718W%20%5C%2C%20Pa)
Similarly,
![p_{2} = \frac{4W}{\pi d_{2}^{2}} \, Pa](https://tex.z-dn.net/?f=p_%7B2%7D%20%3D%20%20%5Cfrac%7B4W%7D%7B%5Cpi%20d_%7B2%7D%5E%7B2%7D%7D%20%5C%2C%20Pa)
![\frac{p_{1}}{p_{2}} = \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp_%7B1%7D%7D%7Bp_%7B2%7D%7D%20%3D%20%20%5Cfrac%7B20.3718%20%5Cpi%20d_%7B2%7D%5E%7B2%7D%7D%7B4%7D%20%3D%2016%20d_%7B2%7D%5E%7B2%7D)
Because p₁/p₂ = T₁/T₂, therefore
![16d_{2}^{2} = \frac{293}{423} \\\\ d_{2}^{2} = \frac{0.6927}{16} \\\\ d_{2} = 0.2081 \, m](https://tex.z-dn.net/?f=16d_%7B2%7D%5E%7B2%7D%20%3D%20%20%5Cfrac%7B293%7D%7B423%7D%20%20%5C%5C%5C%5C%20d_%7B2%7D%5E%7B2%7D%20%3D%20%20%5Cfrac%7B0.6927%7D%7B16%7D%20%20%5C%5C%5C%5C%20d_%7B2%7D%20%3D%200.2081%20%5C%2C%20m)
The minimum piston diameter at 150 C is 20.8 cm.
Answer: 20.8 cm diameter