Question

A point charge Q is placed at the center of a cube of side l. what is the flux through one face of the cube?

Answer 1

Answer:

$\phi=\dfrac{q}{6\epsilon_o}$

Explanation:

A point charge Q is placed at the center of a cube of side l.

We need to find the flux through one face of the cube. Let the flux is $\phi$.

There are 6 faces in a cube.

According to Gauss's law, net flux is given by :

$\phi=\dfrac{q}{\epsilon_0}$

As there are 6 faces of a cube, flux through one surface is :

$6\phi=\dfrac{q}{\epsilon_o}\\\\\phi=\dfrac{q}{6\epsilon_o}$

So, the flux through one face of the cube is $\dfrac{q}{6\epsilon_o}$.