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Rom4ik [11]
3 years ago
11

A point charge Q is placed at the center of a cube of side l. what is the flux through one face of the cube?

Physics
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

\phi=\dfrac{q}{6\epsilon_o}

Explanation:

A point charge Q is placed at the center of a cube of side l.

We need to find the flux through one face of the cube. Let the flux is \phi.

There are 6 faces in a cube.

According to Gauss's law, net flux is given by :

\phi=\dfrac{q}{\epsilon_0}

As there are 6 faces of a cube, flux through one surface is :

6\phi=\dfrac{q}{\epsilon_o}\\\\\phi=\dfrac{q}{6\epsilon_o}

So, the flux through one face of the cube is \dfrac{q}{6\epsilon_o}.

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