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erica [24]
2 years ago
7

A ball is thrown vertically upward at 24.0 ms can reach a height of 28.8m ( neglecting air resistance).The speed,in m/s,when it

is halfway to its highest point is (using g= 10 ms ^2)
Physics
1 answer:
ICE Princess25 [194]2 years ago
3 0

Answer:

The answer is "16.79\ \frac{m}{s}"

Explanation:

In this question, the halfway indicates the height that is \frac{28.8}{2}=14.4 \ m

Using formula:

v^2=u^2+2as\\\\v^2=24^2+2(-10)(14.4)\\\\

v^2=576-288\\\\v^2=288\\\\v=\sqrt{288}\\\\v=16.97 \ \frac{m}{s}

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Answer:

The answer is A

Explanation:

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3 years ago
A 40.0-mH inductor is connected to a North American electrical outlet (ΔVrms = 120 V, f = 60.0 Hz). Assuming the energy stored i
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Explanation:

It is given that,

Inductance, L=40\ mH=40\times 10^{-3}\ H  

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Frequency, f = 60 Hz

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The current flowing through the inductor is given by :

I_t=\dfrac{V_o}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})

I_t=\dfrac{\sqrt{2} V_{rms}}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})

I_t=\dfrac{120\sqrt{2}}{2\pi f L}\ sin(2\pi f t-\dfrac{\pi}{2})

I_t=\dfrac{120\sqrt{2}}{2\pi\times 60\times 40\times 10^{-3}}\ sin(2\pi \times 60\times \dfrac{1}{185})-\dfrac{\pi}{2})    

I_t=\dfrac{120\sqrt2}{15.07}\ sin(2\pi \times 60\times \dfrac{1}{185}-\dfrac{\pi}{2})

I = 0.091 A

Energy stored in the inductor is, U=\dfrac{1}{2}LI^2

U=\dfrac{1}{2}\times 40\times 10^{-3}\times (0.091)^2

U = 0.000165 Joules

Hence, this is the required solution.

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3 years ago
What is the purpose of the author’s description of Montresor’s encounter with Fortunato above? The author is giving the reader a
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3 years ago
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For a particular pipe in a pipe-organ, it has been determined that the frequencies 296 Hz and 370 Hz are two adjacent natural fr
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Answer:

fundamental frequency of pipe will be equal to 74 Hz

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We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz

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3 years ago
What is the magnitude of electrical force of attraction between an copper nucleus (29 protons) and its innermost electron if the
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The charge of the copper nucleus is 29 times the charge of one proton:
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the charge of the electron is
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The magnitude of the electrostatic force between them is given by:
F=k_e  \frac{Qe}{r^2}
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3 years ago
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