Question

A ball is thrown vertically upward at 24.0 ms can reach a height of 28.8m ( neglecting air resistance).The speed,in m/s,when it is halfway to its highest point is (using g= 10 ms ^2)

Answer 1

Answer:

The answer is "$16.79\ \frac{m}{s}$"

Explanation:

In this question, the halfway indicates the height that is $\frac{28.8}{2}=14.4 \ m$

Using formula:

$v^2=u^2+2as\\\\v^2=24^2+2(-10)(14.4)$

$v^2=576-288\\\\v^2=288\\\\v=\sqrt{288}\\\\v=16.97 \ \frac{m}{s}$