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2 years ago

7

A ball is thrown vertically upward at 24.0 ms can reach a height of 28.8m ( neglecting air resistance).The speed,in m/s,when it

is halfway to its highest point is (using g= 10 ms ^2)

1 answer:

ICE Princess25 [194]2 years ago

3 0

Answer:

The answer is " $16.79\ \frac{m}{s}$ "

Explanation:

In this question, the halfway indicates the height that is $\frac{28.8}{2}=14.4 \ m$

Using formula:

$v^2=u^2+2as\\\\v^2=24^2+2(-10)(14.4)\\\\$

$v^2=576-288\\\\v^2=288\\\\v=\sqrt{288}\\\\v=16.97 \ \frac{m}{s}$

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den301095 [7]

Answer:

$\theta=7^o$

Explanation:

<u>Displacement</u>

It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.

The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

$\vec r_1=\ km$

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

$\vec r_2=\ km=\ km$

Finally, he drives 9.5 km 35° north of east.

$\vec r_3=\ km=\ km$

The total displacement is

$\vec r_t=\ km+\ km+\ km$

$\vec r_t=\ km$

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Rzqust [24]

Answer:

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Explanation:

Given that,

Velocity $v= 0.949\times10^{6}\ m/s$

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