The length of a rectangle is 4 cm less than twice the width. express as an integer the maximum width of the rectangle when the perimeter is less than 78 cm.
Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:
180
60
40
Step-by-step explanation:
Angles in a triangle add up to equal 90 degrees
Equilateral - has all congruent angles and congruent sides
If a triangle has 3 angles and the angles add up to equal 180 then the measure of one angle in an equilateral = 180 / 3 = 60
Bisect means to split into to equal parts
So if you bisect an 80 degree angles you will have two 40 degree angles. ( Because 80/2 = 40 )
I believe the answer is A
Answer: Option A. The solution set is (4,5)
Step-by-step explanation:
Solve the equation for<em> </em>y to obtain the form of the equation of the line.
You have:
y=-x+9 (The slope is -1 and the y-intercept is 9)
y=x+1 (The slope is 1 and the y-intercept is 1)
When you graph it you obtain the graph shown in the figure attached.
The solution is the intersection of the lines.
Then, the solution set is (4,5)