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butalik [34]
3 years ago
15

A cinder block is sitting on a platform 10 m high. It has a mass of 25 Kg. What is the potential energy

Physics
1 answer:
mash [69]3 years ago
8 0

Answer:

2450J

Explanation:

PE = mgh

PE = (25)(9.8)(10)

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A proton enters a uniform magnetic field of strength 0.5 T at 200 m/s. The magnetic field is oriented at an angle of 30° to the
-BARSIC- [3]
<h2>The force experienced is 8 x 10⁻¹⁸ N</h2>

Explanation:

When any charge moves into the magnetic field , it experiences the force

The force can be calculated by the relation F = q v B sinθ

here q is the charge and v is its velocity .

B is magnetic field strength and θ is the angle between field and velocity vectors .

Thus F = 1.6 x 10⁻¹⁹ x 200 x 0.5 x  sin 30

=  8 x 10⁻¹⁸ N

8 0
4 years ago
Why is the law of gravity an example of a universal law?
Greeley [361]

Answer:

A

Explanation:

The most important part about this is not only that objects pull on each other, but that two objects attract each other with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them. This is known as Newton's law of universal gravitation.

8 0
4 years ago
Read 2 more answers
Peter and Fred are skateboarding in a large semicircular halfpipe. Peter starts out from rest at a height h and collides with Fr
jolli1 [7]

Answer:

The answer is h/4

Explanation:

When Peter collides with Fred, the collision is inelastic & they both proceed with a velocity of V/2.

let m represent the masses for Peter & Fred

v represent the initial velocity of Peter

V represent final velocity of both of them

mv + 3m × 0 = (m+m)V

V = v/2

Using the expression; H = v² / 2g .............Eqn 1

Upon substitution of V/2 into Eqn 1 above,

H = (V/2)² / 2g

H = (V²/4) ÷ 2g

Therefore height will be h/4

6 0
3 years ago
Write Newton's 3rd law. How would this law relate to a rocket ship taking off from the earth? Would this law affect the rocket s
irina1246 [14]

Answer:

Part A

Newton's 3rd law states that action and reaction are equal and opposite, mathematically, we have;

F_A = -F_B

Where;

F_A = The action force

F_B = The reaction force

Part B

The law indicates that the force with which a rocket ship uses in taking off from the Earth, F_A is equal in magnitude, and opposite in direction to the reaction force of the Earth to the motion of the rocket, (-)F_B

Part C

The law is a universal law, and it will also affect the rocket ship in space, as the force of the jet from the exhaust is directed towards Earth while in space, the rocket is propelled deeper into space

Explanation:

6 0
3 years ago
14. A ball initially at rest rolls without slipping
elena-s [515]

Answer:

v = √(10gh/7)

Explanation:

Initial gravitational energy = final rotational energy + kinetic energy

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For a solid sphere, I = ⅖ mr².

For rolling without slipping, ω = v/r.

mgh = ½ (⅖ mr²) (v/r)² + ½ mv²

mgh = ⅕ mv² + ½ mv²

mgh = 7/10 mv²

10/7 gh = v²

v = √(10gh/7)

7 0
3 years ago
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