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a_sh-v [17]
1 year ago
6

How do you find the oscillation period in seconds for different pendulum lengths?

Physics
1 answer:
GalinKa [24]1 year ago
3 0

To find:

The equation to find the period of oscillation.

Explanation:

The period of oscillation of a pendulum is directly proportional to the square root of the length of the pendulum and inversely proportional to the square root of the acceleration due to gravity.

Thus the period of a pendulum is given by the equation,

T=2\pi\sqrt{\frac{L}{g}}

Where L is the length of the pendulum and g is the acceleration due to gravity.

On substituting the values of the length of the pendulum and the acceleration due to gravity at the point where the period of the pendulum is being measured, the above equation yields the value of the period of the pendulum.

Final answer:

The period of oscillation of a pendulum can be calculated using the equation,

T=2\pi\sqrt{\frac{L}{g}}

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Answer: 2200J

Explanation:

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How much pressure is applied to the ground
statuscvo [17]

Answer:

Pressure applied by the man= 285103.125 Pa  or 41.35 lb/in^{2}

Explanation:

Pressure is defined as the perpendicular force applied per unit area.

i.e.  Pressure=\frac{Force}{Area}

Now, Force= mg

where, m = mass of the body(man) = 93 kg

g = acceleration due to gravity of Earth = 9.81 m/{s^{2}}

Area covered is equal to the area of both stilts(a man generally stands on two feet)

therefore Area=2(0.04)^{2} m^{2}

and putting in the values, we get,

Pressure=\frac{93\times9.81}{2\times(0.04)^{2}}Nm^{-2}=285103.125Nm^{-2}

Now we need to convert to our required units:

1Nm^{-2}=1Pa\\1Pa=0.000145038lb/in^{2}

(We can get the above result by individually converting kg to lb and meters to inches respectively)

Using the above relations we get,

Pressure=285103.125Pa=0.000145038\times285103.125lb/in^{2}=41.35lb/in^{2}

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X = 20 <br> v = 3.5 m/s <br> t = ?
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