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a_sh-v [17]
7 months ago
6

How do you find the oscillation period in seconds for different pendulum lengths?

Physics
1 answer:
GalinKa [24]7 months ago
3 0

To find:

The equation to find the period of oscillation.

Explanation:

The period of oscillation of a pendulum is directly proportional to the square root of the length of the pendulum and inversely proportional to the square root of the acceleration due to gravity.

Thus the period of a pendulum is given by the equation,

T=2\pi\sqrt{\frac{L}{g}}

Where L is the length of the pendulum and g is the acceleration due to gravity.

On substituting the values of the length of the pendulum and the acceleration due to gravity at the point where the period of the pendulum is being measured, the above equation yields the value of the period of the pendulum.

Final answer:

The period of oscillation of a pendulum can be calculated using the equation,

T=2\pi\sqrt{\frac{L}{g}}

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What does the term “retroperitoneal” mean in the terms of the location of the kidneys ?
lakkis [162]

Answer:

"Retroperitoneal" refers to the back of the peritoneum, the membrane that lines the anatomical space in the abdominal cavity. Kidney stones may cause pain to the organs within the retroperitoneal space. A diagram of the aorta, a retroperitoneal structure.

Explanation:

5 0
2 years ago
A(n) 9.9 g bullet is fired into a(n) 138 g block of wood at rest on a horizontal surface and stays inside. After impact, the blo
kompoz [17]

Answer:

185.25 m/s

Explanation:

consider the motion of the combination of bullet and block after the collision

v₀ = initial speed just after the collision

v' = final speed = 0 m/s

μ = Coefficient of friction = 0.6

g = acceleration due to gravity = 9.8 m/s²

a = acceleration of the combination = - μ g = - (0.6) (9.8) = - 5.88 m/s²

d = stopping distance = 13 m

using the kinematics equation

v'² = v₀² + 2 a d

0² = v₀² + 2 (- 5.88) (13)

v₀ = 12.4 m/s

m = mass of the bullet = 9.9 g = 0.0099 kg

M = mass of the wood = 138 g = 0.138 kg

v = speed of bullet before collision

v₀ = speed of combination after the collision = 12.4 m/s

Using conservation of momentum

m v = (m + M) v₀

(0.0099) v = (0.0099 + 0.138) (12.4)

v = 185.25 m/s

3 0
2 years ago
A projectile is fired with an initial speed of 51.2 m/s at an angle of 44.5 degrees above the horizontal on a long flat firing r
irinina [24]
Use the projectile motion equations

H = v^2 x sin^2(θ) ÷ 2g

t = 2 x v x sinθ ÷ g

R = v^2 x sin2θ ÷ g
3 0
2 years ago
At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 8.00 ✕ 106 m/s pe
KonstantinChe [14]

Answer:

4347.8 m/s  

Explanation:

It is given that the radius of the circular path traversed by proton and electron is same. Also, we know that magnitude of charge on an electron and proton is same. Magnetic field strength is same for both.

\frac{m_ev_e^2}{r}=qv_eB\\\frac{m_pv_p^2}{r}=qv_pB\\

Take the ratio:

m_ev_e=m_pv_p\\\Rightarrow v_p=\frac{m_e}{m_p}v_e\\\Rightarrow v_p=\frac{1}{1840}\times 8.0\times 10^6 m/s\\\Rightarrow v_p=4347.8m/s

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3 years ago
State the factors that affect tha gravitational force​
sweet [91]

Explanation:

1. Mass of an object

2. Distance between the objects

7 0
2 years ago
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