Question

A 32.8 g sample of gas occupies 22.414 L at STP. What is the molecular weight of this gas?

Answer 1

Answer:

32.8g/mole

Explanation:

Given parameters:

Mass of sample of gas = 32.8g

Volume  = 22.4L

Unknown:

Molecular weight  = ?

Solution:

To solve this problem we must understand that at rtp;

             1 mole of gas occupies a volume of 22.4L

 

Number of mole of the gas  = 1 mole

 Now;

   Mass  = number of moles x molecular weight

    molecular weight  = $\frac{mass}{molecular weight}$    = $\frac{32.8g}{1mole }$      = 32.8g/mole