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2 years ago

A 32.8 g sample of gas occupies 22.414 L at STP. What is the molecular weight of this gas?

Chemistry

1 answer:

olasank [31]2 years ago

8 0

Answer:

32.8g/mole

Explanation:

Given parameters:

Mass of sample of gas = 32.8g

Volume = 22.4L

Unknown:

Molecular weight = ?

Solution:

To solve this problem we must understand that at rtp;

1 mole of gas occupies a volume of 22.4L

Number of mole of the gas = 1 mole

Now;

Mass = number of moles x molecular weight

molecular weight = $\frac{mass}{molecular weight}$ = $\frac{32.8g}{1mole }$ = 32.8g/mole

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What do you understand by shared pair of electron

PilotLPTM [1.2K]

Answer:Lone pairs are the valence electron pair of any element which do not take part in bonding but affect the shape of molecules. Bond pairs or shared pairs are the electron pair which does both affect the geometry of molecules and take part in chemical bonding. These are form due to sharing of electrons.

Explanation:

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3 years ago

Which system consists of nerves that initiate communication?

LenKa [72]

Peripheral nervous system consists of nerves that help in communication among different parts of the body. In nervous system nerves are used to take and deliver messages. These messages are taken from different parts of the body to brain and these nerves are spreading all over the body.

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3 years ago

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a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the

svet-max [94.6K]

Answer: The mass density is 1166.36 $kg/m^{3}$ .

Explanation:

Given: Weight of sample in air $(F_{air})$ = 500 N

Weight of sample in alcohol $(F_{alc})$ = 200 N

Specific gravity = 0.7 = $0.7 \times 1000 = 700 kg/m^{3}$

Formula used to calculate Buoyant force is as follows.

$F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N$

Hence, volume of the material is calculated as follows.

$V = \frac{F_{B}}{\rho \times g}$

where,

$F_{B}$ = Buoyant force

$\rho$ = specific gravity

g = acceleration due to gravity = 9.81

Substitute the values into above formula.

$V = \frac{F_{B}}{\rho \times g}\\= \frac{300}{700 \times 9.81}\\= \frac{300}{6867}\\= 0.0437 m^{3}$

Now, mass of the material is calculated as follows.

$mass = \frac{F_{air}}{g}\\= \frac{500 N}{9.81}\\= 50.97 kg$

Therefore, density of the material or mass density is as follows.

$Density = \frac{mass}{volume}\\= \frac{50.97 kg}{0.0437 m^{3}}\\= 1166.36 kg/m^{3}$

Thus, we can conclude that the mass density is 1166.36 $kg/m^{3}$ .

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2 years ago

Which chemical property deals with the ability of a substance being able to

Fantom [35]

$\large\underline{\bf\red{Solution:-}}$

The chemical property deals with the ability of a substance being able to burn is called combustibility [ option b ] .

More to know :-

1) Combustion :-

Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives out heat.

The fuel can be any one of the 3 states of matter that is - solid , liquid & gases .

Examples of combustible substances :-

Solid - Coal

Liquid - Petrol , Disel , etc.

Gas - Hydrogen , Oxygen , etc .

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2 years ago

Read 2 more answers

In the chemical reaction:Br2(g) + Cl2(g) ⇌ 2 BrCl(g) KP = 0.150If there is initially 0.500 atm of BrCl and nothing else in a con

klemol [59]

Answer:

The partial pressure of BrCl at equilibrium is 0.08 atm.

Explanation:

The equilibrium constant of the reaction is given by = $K_p=0.150$

$Br_2(g) + Cl_2(g)\rightleftharpoons 2 BrCl(g)$

initial

0 0 0.500 atm

At equilbrium

p p (0.500-2p)

The equilibrium constant's expression of the reaction is given by ;

$K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}$

$0.150=\frac{(0.500-2p)^2}{p\times p}$

Solving for p:

p = 0.21 atm

The partial pressure of BrCl at equilibrium is:

(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]

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2 years ago