All categories

3 years ago

21) What is the volume (inL) of 3470 g of liquid glycerol, which has a density of 1.26 g/?

Chemistry

1 answer:

Illusion [34]3 years ago

6 0

Answer:

V = 2.75 L

Explanation:

Given that,

Mass of liquid glycerol, m = 3470 g

The density of liquid glycerol, d = 1.26 g/cm³

We need to find the volume of liquid glycerol.

We know that,

Density=mass/volume

$V=\dfrac{m}{d}\\\\V=\dfrac{3470\ g}{1.26\ g/cm^3}\\\\V=2753.96\ cm^3$

We know that, 1 cm³ = 0.001 L

V = 2.75 L

So, the volume of liquid glycerol is 2.75 L.

You might be interested in

A chemist measures the solubility of lead(ii) bromide in water to be 2. 96 g/l. calculate the ksp value for the solid. the ksp v

Julli [10]

The solubility product, ksp of PbBr₂ is 2.102 × 10⁻⁶

<h3>What is solubility?</h3>

The solubility of a solute is defined as the maximum amount of that solute that can be dissolved in a known quantity of solvent at a given temperature.

<h3>What is a solubility product? </h3>

Some salts are sparingly soluble in a solvent. For them, we calculate the solubility product.

It is an equilibrium constant that defines the relationship between a solid and its respective ions in an aqueous solution in equilibrium.

The greater the solubility product, the greater the solubility and vice versa.

Here, the solubility of PbBr₂ = 2.96 g/l

Molar solubility of PbBr₂ = $\frac{2.96}{molar mass of PbBr_2}$ = 2.96/367 = 8.07 × 10⁻³

At equilibrium,

$PbBr_2\rightarrow Pb^{2+} + 2Br^-$

1 mole of PbBr2 dissociates into 1 mole of Pb²⁺ ions and 2 moles of Br⁻

Let the molar concentration of Pb²⁺ be x, then the molar concentration of Br⁻ is 2x

Ksp = x.(2x)²

= 4x³

Substitute, x = 8.07 × 10⁻³

Ksp = 4 (8.07 × 10⁻³)³

= 2.102 × 10⁻⁶

Thus, The ksp of PbBr₂ is 2.102 × 10⁻⁶

Learn more about solubility product:

brainly.com/question/1419865

#SPJ4

5 0

2 years ago

Which of the following is not a step in the conversion of 37 L to dam3?

MArishka [77]

The first one. observe that numerator and denominator are of same type in all other cases. but in 1st one, its length/volume which is crazy. how can one equate length to volume ? no way.

3 0

3 years ago

Is the photon is in the IR, UV or visible portion of the electromagnetic spectrum.

DiKsa [7]

Answer:

The different types of radiation are defined by the the amount of energy found in the photons. Radio waves have photons with low energies, microwave photons have a little more energy than radio waves, infrared photons have still more, then visible, ultraviolet, X-rays, and, the most energetic of all, gamma-rays.Explanation: hope this helps god bless you

8 0

2 years ago

How many grams of potassium bromide, KBr, are in 100mL of a 0.50 M solution?

VMariaS [17]

Answer:

5.95g

Explanation:

1 $dm^{3}$ = 1000 mL

∴ 100 mL = 100 ÷ 1000 = 0.1 $dm^{3}$

Volume = <u>0.1 </u> $dm^{3}$ <u />

Concentration = <u>0.5 M</u>

Concentration = $\frac{No. of moles}{volume}$

0.5 = $\frac{x}{0.1}$

No. of moles = 0.5 x 0.1 = <u>0.05 moles</u>

No. of moles = $\frac{mass}{mass. in. 1. mole}$

Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)

0.05 = $\frac{x}{119}$

x = 119 × 0.05 = 5.95g

4 0

3 years ago

In the reaction Mg (s) + 2HCl (aq) -> H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 300 millilite

d1i1m1o1n [39]

Mg(s) + 2HCl(aq) = H₂(g) + MgCl₂(aq)

v=300 ml=0.3 l
c=4 mol/l

n(HCl)=vc

m(H₂)/M(H₂)=n(HCl)/2

m(H₂)=M(H₂)vc/2

m(H₂)=2.0g/mol·0.3 l · 4mol/l /2 = 1.2 g

1.2 grams of hydrogen gas will be produced

5 0

4 years ago