Question

.

Answer 1

Answer:

$-\frac{1}{2}$

Diverging lens

Explanation:

Given parameters:

Power of lens  = -2.0D

Unknown:

Focal length  = ?

Solution:

The power of lens is the reciprocal of the focal length;

   P  = $\frac{1}{f}$

where  f is the focal length

 f  = $\frac{1}{P}$   = $-\frac{1}{2}$

The lens is a diverging lens