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3 years ago

Anser the photo and i'll give brainlest

Physics

1 answer:

Maurinko [17]3 years ago

5 0

Answer:

6 b

7 d

Explanation:

6. removed anther

7. recessive

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Two one-coulomb point charges are at a distance of 1.67 m from each other. What is the size of the electric force between the tw

pychu [463]

Explanation:

The given data is as follows.

distance (r) = 1.67 m

$q_{1} = q_{2}$ = 1 C

It is known that formula for electric force between two charges is as follows.

F = $\frac{kq_{1} \times q_{2}}{r^{2}}$

Hence, putting the given values into the above formula as follows.

$\frac{9 \times 10^{9} \times 1 \times 1}{(1.67)^{2}}$

= $3.227 \times 10^{9}$

As it is given that mass of Falcon Heavy rocket is 1421. Therefore, weight of 1 Falcon rocket is as follows.

weight of 1 falcon rocket = $142 \times 10^{3} \times 9.8$

Therefore, number of falcon rockets will be calculated as follows.

No. of falcon rockets = $\frac{3.227 \times 10^{9}}{142000 \times 9.8}$

= $2.31897 \times 10^{3}$

= 2318.9 falcons

Thus, we can conclude that force between the two point charges above is equal to the weight of 2318.9 Falcon Heavy rockets.

5 0

3 years ago

How do longitudinal waves transport energy?

marissa [1.9K]

A longitudinal wave transports energy through the medium without permanently transporting matter.

Hope this helps :D

6 0

3 years ago

Did you think about this over Christmas? I did (-: Before Christmas a 65kg student consumes 2500 Cal each day and stays at the s

Gnesinka [82]

Answer:

a) Em = 332.8 J , b) # jump = 13, c) It is reasonable since there are not too many jumps , d) lower the calories consumed

Explanation:

a) Let's use energy conservation

Initial. On the floor

Em₀ = K = ½ m v²

Final. The highest point

Emf = U = m g h

Energy is conserved

Em₀ = Emf

½ m v² = m g h

h = ½ v² / g

h = ½ 3.2² /9.8

h = 0.52 m

b) When he was at home he maintained his weight with 2500 cal / day. In his parents' house he consumes 3500 cal / day, the excess of calories is

Q = 3500 -2500 = 1000cal / day

Let's reduce this value to the SI system

Q = 1000 cal (4,184 J / 1 cal) = 4186 J / day

Now the energy in each jump is

Em = K = ½ m v²

Em = ½ 65 3.2²

Em = 332.8 J

They indicate that the body can only use 25% of this energy

Em effec = 0.25 332.8 J

Em effec = 83.2 J

This is the energy that burns the body

Let's use a Proportion Rule (rule of three), if a jump spends 83.2J how much jump it needs to spend 1046 J

# jump = 1046 J (1 jump / 83.2 J)

# jump = 12.6 jumps / day

# jump = 13

c) It is reasonable since there are not too many jumps

d) That some days consume more vegetables to lower the calories consumed

7 0

4 years ago

A force F acting on an object of mass m causes a displacement d. The angle between these two vectors is Θ. The work W done on th

777dan777 [17]

Work:
$W= \int\limits^b_a {F.} \, ds$

F: force
ds: displacement

Assuming the work is constant:

$W= \int\limits^b_a {F.} \, ds = F . d = F * cos\theta * d$

d displacement

4 0

3 years ago

A body accelerates uniformly from rest at 2m/s square. calculate it's velocity after traveling 9m.

Talja [164]

Answer:

6m/s

Explanation:

Given parameters:

Initial velocity = 0m/s

Acceleration = 2m/s²

Distance = 9m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use the expression below:

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

v² = 0² + (2 x 2 x 9) = 36

v = 6m/s

3 0

3 years ago