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Mademuasel [1]
3 years ago
8

Na (atomic no. 11) reacts with cl (atomic no. 17) to become stable. In the reaction, na will ____________, while cl will _______

_____.Na (atomic no. 11) reacts with cl (atomic no. 17) to become stable. In the reaction, na will ____________, while cl will ____________.
Chemistry
1 answer:
Fynjy0 [20]3 years ago
4 0
<h3>Answer:</h3>

             Na (atomic no. 11) reacts with cl (atomic no. 17) to become stable. In the reaction, Na will <u>give up one electron</u>, while cl will <u>accept on electron</u>.

<h3>Explanation:</h3>

                   NaCl is formed by Na⁺ cation and Cl⁻ anion as follow,

Oxidation of Na;

                                     Na  →  Na⁺  +  1 e⁻

In this step sodium looses one electron due to less ionization energy as the resulting Na⁺ ion has attained a stable noble gas configuration of Neon (i.e. 1s², 2s², 2p⁶).

Reduction of Cl₂;

                                   Cl₂  +  2 e⁻  →  2 Cl⁻

In this step each Chlorine atom accepts one electron and forms Chloride ion (Cl⁻). Again the driving force for this step is attaining the noble gas configuration of Argon (i.e. 1s², 2s², 2p⁶, 3s², 3p⁶).

Crystal Lattice formation is as follow,

                                 Na⁺  +  Cl⁻   →  NaCl


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Given data:

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