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Olin [163]
2 years ago
7

What are areas of the workforce can science be applied to

Chemistry
1 answer:
Amanda [17]2 years ago
6 0

Answer: Government regulation, healthcare, telemarketing, environmental engineering, banking.

Explanation:

Science is the set of objective and verifiable information about all areas of human knowledge. To create knowledge, science uses the scientific method, this method explains, formulates and verifies a hypothesis about a concept.

 

Science can be used in all professional fields because it allows for obtaining objective information or knowledge. For example, in government regulation, the scientific method can be implemented to make objective decisions about decisions that will best help the population.

I hope this information can help you.

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A student used standard solutions of aspirin in a FeCl3-KCl-HCl mixture to plot a graph of molarity versus absorbance for dilute
kvasek [131]

Answer:

is any thing which has mass volume and empty space

8 0
2 years ago
Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
How many of the following statements about silver acetate, AgCH3COO, are true? i) More AgCH3CoO(S) will dissolve if the pH of th
shutvik [7]

Answer:

All three statements are true

Explanation:

Solubility equilibrium of silver acetate:

AgCH_{3}COO\rightleftharpoons Ag^{+}+CH_{3}COO^{-}

  • If pH is increased then concentration of H^{+} increases in solution resulting removal of CH_{3}COO^{-} by forming CH_{3}COOH. Hence, according to Le-chatelier principle, equilibrium will shift towards right. So more AgCH_{3}COO will dissolve
  • If AgNO_{3} is added then concentration of Ag^{+} increases in solution resulting shifting of equilibrium towards left in accordance with Le-chatelier principle. So less AgCH_{3}COO will dissolve
  • Insoluble precipitate of AgOH is formed by adding NaOH in solution resulting removal of Ag^{+}. So, more AgCH_{3}COO will dissolve

Hence all three statements are true

8 0
3 years ago
Sodium metal reacts with water to produce hydrogen gas and sodium hydroxide according to the chemical equation shown below.
UNO [17]

<u>Answer:</u> The enthalpy change of the reaction is -361.6 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sodium = 0.025 moles

Molar mass of sodium = 23 g/mol

Putting values in above equation, we get:

0.025mol=\frac{\text{Mass of sodium}}{23g/mol}\\\\\text{Mass of sodium}=(0.025mol\times 23g/mol)=0.575g

We are given:

Mass of water = 100.00 g

Mass of sodium = 0.575 g

Mass of solution = 100.00 + 0.575 = 100.575 g

To calculate the amount of heat absorbed, we use the equation:

q=m\times C\times \Delta T

where,

q = amount of heat absorbed = ?

m = mass of solution = 100.575 g

C = specific heat capacity of solution = 4.18 J/g°C

\Delta T = change in temperature = (T_2-T_1)=(35.75-25.00)=10.75^oC

Putting all the values in above equation, we get:

q=100.575g\times 4.18J/g^oC\times 10.75^oC=4519.34J=4.52kJ

When heat is absorbed by the solution, this means that heat is getting released by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

For the given chemical reaction:

2Na(s)+2H_2O(l)\rightarrow NaOH(aq.)+H_2(g)

When 0.025 moles of sodium is reacted, the heat released by the reaction is 4.52 kJ

So, when 2 moles of sodium will react, the heat released by the reaction will be = \frac{4.52}{0.025}\times 2=361.6kJ

Hence, the enthalpy change of the reaction is -361.6 kJ

6 0
3 years ago
Calculate the pH of a 3.58x10^-9 M Nitric acid (a strong acid) solution
lubasha [3.4K]

Answer:

pH= 8.45

Explanation:

when working with strong accids pH = -log(Concentration)

so -log(3.58e-9) = 8.446

7 0
3 years ago
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