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3 years ago

What are areas of the workforce can science be applied to

Chemistry

1 answer:

Amanda [17]3 years ago

6 0

Answer: Government regulation, healthcare, telemarketing, environmental engineering, banking.

Explanation:

Science is the set of objective and verifiable information about all areas of human knowledge. To create knowledge, science uses the scientific method, this method explains, formulates and verifies a hypothesis about a concept.

Science can be used in all professional fields because it allows for obtaining objective information or knowledge. For example, in government regulation, the scientific method can be implemented to make objective decisions about decisions that will best help the population.

I hope this information can help you.

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Which is an example of a covalent bond? Chlorine accepts an electron from calcium to form a stable bond. Ions in a bar of pure i

Ivenika [448]

Chlorine + Calcium --> Ionic Bond
Iron cannot covalently bond as it is a metal

4 0

3 years ago

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2. What mass of sodium chloride is produced when chlorine gas reacts with 2.29 grams of sodium iodide? The unbalanced equation i

Damm [24]

Answer:

0.88g

Explanation:

The reaction equation:

2NaI + Cl₂ → 2NaCl + I₂

Given parameters:

Mass of Sodium iodide = 2.29g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we work from the known to the unknown.

First find the number of NaI from the mass given;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of NaI = 23 + 126.9 = 149.9g/mol

Now insert the parameters and solve;

Number of moles = $\frac{2.29}{149.9}$ = 0.015mol

So;

From the balanced reaction equation;

2 moles of NaI produced 2 moles of NaCl

0.015mole of NaI will produce 0.015mole of NaCl

Therefore;

Mass = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Now;

Mass of NaCl = 0.015 x 58.5 = 0.88g

8 0

2 years ago

You wish to make a 0.375 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid

cluponka [151]

We need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

You are performing a dilution of HBr going from a concentration of 12M to 0.335M, and you want to end up with a final volume of 75 ml of the dilute solution.

Consider the dilution formula: M1V1 = M2V2.

The basis behind this formula is that the number of moles of the acid before and after the dilution must remain constant.

M1 = the molarity of the stock solution,

M2 = the molarity of the diluted solution,

V2 = the final volume of the diluted solution.

In this case, we need to determine V1, which is the volume of the stock solution used to prepare the diluted sample. With this knowledge, we can plug our numbers into the equation and we obtain the following:

(12 mol/L)*V1 = (0.335mol/L)*(0.075L).

Keeping in mind that molarity is the moles of a substance in one liter of solution, we will use mol/L instead of M. By doing this, we are reminded that in order to use this equation, we must convert 75 mL into units of liters.

After rearranging the equation and solving for V1, we find that V1 = 0.00209L.

Finally, we must convert back from liters to mL by multiplying the final answer by 1000.

This way we end up with V1 = 2.09 mL.

This means that we need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

Learn more about molarity here: brainly.com/question/23243759

#SPJ4

3 0

2 years ago

What type of precipitation occurs when the temperature of the sky is above freezing? Below

Shkiper50 [21]

Answer:

Above freezing :- rain

Below freezing :- hail

6 0

2 years ago

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Classify the reaction by their type. Note there may be more than one way to classify a reaction.

Nadya [2.5K]

Answer:

Redox reaction and single displacement

Explanation:

This reaction is first of all a redox reaction. A redox reaction is a reaction that involves both oxidation and reduction. Oxidation involves increase in oxidation number while reduction involves decrease in oxidation number.

Copper (Cu) had an oxidation number of "0" as a reactant but had an oxidation number of "2+" in the product [Cu(NO₃)₂] hence oxidation occurred.

Nitrogen (N) had an oxidation number of "5+" in the reactant (HNO₃) but had an oxidation number of "4+" in the product (NO₂) hence reduction also occurred.

Also, from the reaction, it can be deduced that copper (Cu) displaced hydrogen (H) from the nitric acid (HNO₃) solution to form copper (II) nitrate [Cu(NO₃)₂]. It should be noted that copper can displace hydrogen because it is higher than hydrogen in the electrochemical series. Hence, this reaction can also be called a single displacement reaction. A single displacement reaction is a reaction in which an atom of an element replaces another atom in a compound (as seen in the equation given in the question).

3 0

3 years ago