Answer:
4. Atoms in crystals are in an ordered array. In amorphous materials, they are randomly distributed.
Explanation:
Amount of substance can be measured in the number of moles.
Avagadros constant states that 1 mol of any substance is made of 6.022 x 10^23 units.
These units could be atoms making up elements or molecules making up compounds
1 mol of C is made of 6.022 x 10^23 atoms of C
Since 1 mol of C has a mass of 12.011 g
Therefore 6.022 x 10^23 atoms of C weigh 12.011 g
Then 1 atom of C weighs -12.011 g / 6.022 x 10^23 atoms = 1.99 x 10^(-23) g
Mass of 1 C atom is 1.99 x 10^(-23) g
If a solid changes right to a gas, it's called sublimation. If a gas changes directly to a solid, it's called deposition.
Answer: The value of the equilibrium constant for this reaction is 
Explanation:
To calculate the moles, we use the equation:
Moles of 
= 
Moles of 
= 
Moles of 
= 
Volume of solution = 2.7 L
Equilibrium concentration of = 
Equilibrium concentration of = 
Equilibrium concentration of = 
The given balanced equilibrium reaction is,
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Ni]^1\times [CO]^4}{[Ni(CO_4]^1}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNi%5D%5E1%5Ctimes%20%5BCO%5D%5E4%7D%7B%5BNi%28CO_4%5D%5E1%7D)
Now put all the given values in this expression, we get :
Thus the value of the equilibrium constant for this reaction is
Explanation:
To calculate [H3O+] in the solution we must first find the pH from the [ OH-]
That's
pH + pOH = 14
pH = 14 - pOH
To calculate the pOH we use the formula
pOH = - log [OH-]
And [OH-] = 5.5 × 10^-5 M
So we have
pOH = - log 5.5 × 10^ - 5
pOH = 4.26
Since we've found the pOH we can now find the pH
That's
pH = 14 - 4.26
pH = 9.74
Now we can find the concentration of H3O+ in the solution using the formula
pH = - log H3O+
9.74 = - log H3O+
Find the antilog of both sides
<h2> H3O+ = 1.8 × 10^ - 10 M</h2>
The solution is basic since it's pH lies in the basic region.
Hope this helps you
