Answer: When the reaction reaches equilibrium, the cell potential will be 0.00 V
Explanation:
Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.
The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.
The standard emf of a cell is related to Gibbs free energy by following relation:

The Gibbs free energy is related to equilibrium constant by following relation:

For equilibrium 
Thus 

Thus When the reaction reaches equilibrium, the cell potential will be 0.00 V
Most likely to be found is called an Orbital.
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If it loses 1 electron, it will now have 1 more proton than electrons.
Thus, the charge would be 1+
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<u>Answer:</u> The correct answer is Option 4: U
<u>Explanation:</u>
Activation energy is defined as the energy that is given to a chemical system with potential reactants to produce products. It is represented as 
It is represented as the energy from the reactants to the activated complex.
Reverse reaction is defined as the reaction in which the products formed become reactants and leads to the formation of reactants back.
So, here, the activation energy of the reverse reaction is the energy between the products and the activated complex, which is represented as letter U in the given graph.
Hence, the correct answer is Option 4: U