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Korvikt [17]
3 years ago
5

Identify the followings as a element or compound c12 h22o11

Chemistry
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

Compound

Explanation:

The given specie is a compound.

A compound is made up of two or more kinds of atoms/elements joined together in a definite grouping.

  • The properties of a compound are distinct and different from those of the individual elements that are combined in its make-up.
  • For this given specie, the elements are carbon, hydrogen and oxygen.
  • So, this is a compound.

Elements are distinct substances that cannot be split - up into simpler substances. Such substances consist of only one kind of atom

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Which class of compounds does ammonia blog
Igoryamba
T'belongs to the hydrides, it's a nitrogen hydride. 
8 0
3 years ago
Which is the most likely to be reduced?
NISA [10]

Answer : The correct option is, Zn^{2+}

Explanation :

  • Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. That means, the loss of electrons takes place.

Or we can say that, oxidation reaction occurs when a reactant losses electrons in the reaction.

  • Reduction reaction : It is defined as the reaction in which a substance gains electrons. That means, the gain of electrons takes place.

Or we can say that, reduction reaction occurs when a reactant gains electrons in the reaction.

According to the electrochemical series, Zn^{2+} most likely to be reduced because

Hence, the ion most likely to be reduced is Zn^{2+}.

3 0
2 years ago
Explain how the relative atomic mass and the mass number of elements are different and hence why some elements have relative ato
padilas [110]
This is because the relative atomic mass is the sum of the no of protons and neutrons while the atomic no is of the former only. it is not a whole number it is th average weighted masses of the various isotopes of the element multiplied by their corresponding relative abundance. pls thank me and mark me briniest 
6 0
3 years ago
For which of the following elements would the most common ion be expected to have a larger radius than that of its corresponding
Andre45 [30]

<u>Answer:</u> The ion that is expected to have a larger radius than the corresponding atom is chlorine.

<u>Explanation:</u>

There are two types of ions:

  • <u>Cations:</u> They are formed when an atom looses its valence electrons. They are positive ions.
  • <u>Anions:</u> They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. So, the effective nuclear charge increases for cations and thus, the size of the cation will be smaller than that of the corresponding atom.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. So, the effective nuclear charge decreases for anions and thus, the size of the anion will be larger than that of the corresponding atom.

For the given options:

<u>Option a:</u> Chlorine

Chlorine gains 1 electron and form Cl^- ion

<u>Option b:</u> Sodium

Sodium looses 1 electron and form Na^+ ion

<u>Option c:</u> Copper

Copper looses 2 electrons and form Cu^{2+} ion

<u>Option d:</u> Strontium

Strontium looses 2 electrons and form Sr^{2+} ion

Hence, the ion that is expected to have a larger radius than the corresponding atom is chlorine.

8 0
3 years ago
Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl
tensa zangetsu [6.8K]

Answer:

[SO_2Cl_2] = 0.09983 M

Explanation:

Write the balance chemical equation ,

SO_2Cl_2((g) = SO_2(g) + Cl_2(g)

initial concenration of SO_2Cl_2((g)  =0.1M

lets assume that degree of dissociation=\alpha

concenration of each component at equilibrium:

[SO_2Cl_2] = 0.1-0.1\alpha

[SO_2] = 0.1\alpha

[Cl_2] = 0.1\alpha

Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}

Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}

as \alpha is very small then we can neglect  1-\alpha

therefore ,

Kc ={0.1\alpha \times \alpha}

\alpha =\sqrt{\frac{Kc}{0.1}}

\alpha = 1.73 \times 10^{-3}

Eqilibrium concenration of [SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173

[SO_2Cl_2] = 0.09983 M

4 0
3 years ago
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