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grin007 [14]
2 years ago
9

How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s2? a 1003 N b 0.003 N c 3000 N d 333.3 N

Chemistry
1 answer:
Bogdan [553]2 years ago
7 0

Answer:

Option c.

Explanation:

According to Newton's law, formula to solve this problem is:

F = m . a

Mass → 1000 kg

a → 3 m/s²

F = 1000 kg . 3m/s² →  3000 N

1 N = 1 kg .  m/s²  according to SI, Internation System of units.

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Which of these does not describe the Wright brothers' first attempts at flight?
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They mimicked the flight of birds.

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How many molecules are in 5.50 grams of AgNO3?
mixas84 [53]

Answer:

1.95*10²² molecules are in 5.50 grams of AgNO₃

Explanation:

Being the molar mass of the elements:

  • Ag: 107.87 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

then the molar mass of the compound is:

AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole

Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?

moles=\frac{5.50 grams*1 mole}{169.87 grams}

moles= 0.0324

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?

molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}

molecules=1.95*10²²

<u><em>1.95*10²² molecules are in 5.50 grams of AgNO₃</em></u>

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If a tank of gas contains 4 L of N O2 how many molecules are in it
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but heres a way to solve it

An athlete takes a deep breath, inhaling 1.85 L of air at 21°C and 754 mm Hg.

T

How many moles of air are in the breath? How many molecules?

Gas constant, R= 8.314 J mol ¹ K-1

PV = nRT

PV

RT

h=

=

P

= 0.08206 L atm mol-1 K-1

= 62.36 L Torr mol-1 K-1 -

1 atm = 760 mm Hg = 760 Torr

754 Forr 1.85€

6236 Jerr 294K

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Answer:

8.21

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