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Elza [17]
3 years ago
15

Please help me 1,2,3 or 4

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0

Answer:

2x + 4 < 9 \\ 2x < 9 - 4 \\ 2x < 5 \\ x <  \frac{5}{2}  \\ x < 2.5

hence only (4) => 3 cannot be the answer, because it is greater than x

Novay_Z [31]3 years ago
3 0

Answer:

number 2 with is number 1

Step-by-step explanation:

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In triangle NLM, point S is the centroid, QS = (3x – 5) cm, and NS = (4x) cm. What is NS? 5 cm 10 cm 20 cm 30 cm
son4ous [18]

Answer:

20 cm

Step-by-step explanation:

∵ S is the centroid of ΔNLM

∴ S divides NG at ratio 1 : 2 from the base

∴SQ = 1/2 NS

∴3x - 5 = 1/2 (4x)

∴3x - 5 = 2x

∴3x - 2x = 5

∴x = 5

∴ NS = 4 × 5 = 20 cm

5 0
3 years ago
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(12)2what does it equal
julia-pushkina [17]
12 × 2 = 24

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7 0
3 years ago
Which one is cheaper and why
Shtirlitz [24]

Hey there! :)

Answer:

The bag is cheaper because one litre is roughly $1.00, compared to the carton which is $1.99 for one litre.

Step-by-step explanation:

Given:

Bag of 4 litre milk = $3.99

Carton of 1 litre milk = $1.99

Find the price per litre for a bag of milk:

\frac{3.99}{4} = \frac{x}{1}

Cross multiply:

3.99 = 4x

Divide both sides by 4:

3.99/4 = x.

x = 0.9975 ≈ $1.00

Bag of 1 litre milk ≈ $1.00

Carton of 1 litre milk = $1.99

$1.00 < $1.99

Therefore, the bag is cheaper.

5 0
3 years ago
The floor of a shed has an area of 108 ft. The floor is a rectangle whose length is 6 feet less than twice the width. Find the w
Lesechka [4]


A = L x W

A = 108

108 = L x W

L = 2w - 6

108 = (2w-6) (W)

7 0
3 years ago
Given below are the graphs of two lines, y=-0.5 + 5 and y=-1.25x + 8 and several regions and points are shown. Note that C is th
zalisa [80]
We have the following equations:

(1) \ y=-0.5x+5 \\ (2) \ y=-1.25x+8

So we are asked to write a system of equations or inequalities for each region and each point.

Part a)

Region Example A

y \leq -0.5x+5 \\ y \leq -1.25x+8

Region B.

Let's take a point that is in this region, that is:

P(0,6)

So let's find out the signs of each inequality by substituting this point in them:

y \ (?)-0.5x+5  \\ 6 \ (?) -0.5(0)+5 \\ 6 \ (?) \ 5 \\ 6\ \textgreater \ 5 \\  \\ y \ (?) \ -1.25x+8 \\ 6 \ (?) -1.25(0)+8 \\ 6 \ (?) \ 8 \\ 6\ \textless \ 8

So the inequalities are:

(1) \ y  \geq  -0.5x+5 \\  (2) \ y  \leq  -1.25x+8

Region C.

A point in this region is:

P(0,10)

So let's find out the signs of each inequality by substituting this point in them:

y \ (?)-0.5x+5 \\ 10 \ (?) -0.5(0)+5 \\ 10 \ (?) \ 5 \\ 10\ \textgreater \ 5 \\ \\ y \ (?) \ -1.25x+8 \\ 10 \ (?) -1.25(0)+8 \\ 10 \ (?) \ 8 \\ 10 \ \ \textgreater \  \ 8

So the inequalities are:

(1) \ y  \geq  -0.5x+5 \\ (2) \ y  \geq  -1.25x+8

Region D.

A point in this region is:

P(8,0)

So let's find out the signs of each inequality by substituting this point in them:

y \ (?)-0.5x+5 \\ 0 \ (?) -0.5(8)+5 \\ 0 \ (?) \ 1 \\ 0 \ \ \textless \  \ 1 \\ \\ y \ (?) \ -1.25x+8 \\ 0 \ (?) -1.25(8)+8 \\ 0 \ (?) \ -2 \\ 0 \ \ \textgreater \ \ -2

So the inequalities are:

(1) \ y  \leq  -0.5x+5 \\ (2) \ y  \geq  -1.25x+8

Point P:

This point is the intersection of the two lines. So let's solve the system of equations:

(1) \ y=-0.5x+5 \\ (2) \ y=-1.25x+8 \\ \\ Subtracting \ these \ equations: \\ 0=0.75x-3 \\ \\ Solving \ for \ x: \\ x=4 \\  \\ Solving \ for \ y: \\ y=-0.5(4)+5=3

Accordingly, the point is:

\boxed{p(4,3)}

Point q:

This point is the x-intercept of the line:

y=-0.5x+5

So let:

y=0

Then

x=\frac{5}{0.5}=10

Therefore, the point is:

\boxed{q(10,0)}

Part b) 

The coordinate of a point within a region must satisfy the corresponding system of inequalities. For each region we have taken a point to build up our inequalities. Now we will take other points and prove that these are the correct regions.

Region Example A

The origin is part of this region, therefore let's take the point:

O(0,0)

Substituting in the inequalities:

y \leq -0.5x+5 \\ 0 \leq -0.5(0)+5 \\ \boxed{0 \leq 5} \\ \\ y \leq -1.25x+8 \\ 0 \leq -1.25(0)+8 \\ \boxed{0 \leq 8}

It is true.

Region B.

Let's take a point that is in this region, that is:

P(0,7)

Substituting in the inequalities:

y \geq -0.5x+5 \\ 7 \geq -0.5(0)+5 \\ \boxed{7 \geq \ 5} \\ \\ y  \leq \ -1.25x+8 \\ 7 \ \leq -1.25(0)+8 \\ \boxed{7 \leq \ 8}

It is true

Region C.

Let's take a point that is in this region, that is:

P(0,11)

Substituting in the inequalities:

y \geq -0.5x+5 \\ 11 \geq -0.5(0)+5 \\ \boxed{11 \geq \ 5} \\ \\ y \geq \ -1.25x+8 \\ 11 \ \geq -1.25(0)+8 \\ \boxed{11 \geq \ 8}

It is true

Region D.

Let's take a point that is in this region, that is:

P(9,0)

Substituting in the inequalities:

y  \leq -0.5x+5 \\ 0 \leq -0.5(9)+5 \\ \boxed{0 \leq \ 0.5} \\ \\ y \geq \ -1.25x+8 \\ 0 \geq -1.25(9)+8 \\ \boxed{0 \geq \ -3.25}

It is true

7 0
3 years ago
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