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jeyben [28]
3 years ago
14

A test charge of 0.16 C experiences a force of 0.04 N. What is the electric field strength?

Physics
1 answer:
morpeh [17]3 years ago
6 0

Answer:charge and a 0.04 C charge are separated by a distance of 3.0 m. At what position between the two charges would a test charge experience an electric field intensity of zero? Answers 1. The magnitude of the electric field

Explanation:

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The force between two charged bodies is called ______________.
stepladder [879]

The Coulomb force between two or more charged bodies is the force between them due to Coulomb's law. If the particles are both positively or negatively charged, the force is repulsive; if they are of opposite charge, it is attractive. ... Like the gravitational force, the Coulomb force is an inverse square law.

6 0
3 years ago
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Forces can act on an object in the same direction or in opposite. how does each situation affect the motion of the object?
Anon25 [30]



Hi pupil here's your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



Action and Reaction do not act on the same body !! If they acted on the same body, the resultant force will be zero and their could be never accelerated motion.

If both the forces acted on the same body, then if they are equal to opposite direction the object will remain stationary. If on of the forces is greater than other the object will move in the direction of greater force.

If both acted in the same direction there would be an accelrated motion.




⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅





Hope this helps . . . . .
5 0
3 years ago
How much work is done when a porcelain vase with mass of 2.5 kg is lifted up 3 m to a shelf? (HINT- Weight can be used as Force
alexdok [17]
Work = force x distance
F= 2.5
D= 3
Work = 2.5 x 3 =7.5
Work = 7.5 J
J=Jules (Jules is the unit uses to calculate work)
8 0
2 years ago
Assuming 84.0% efficiency for the conversion of electrical power by the motor, what current must the 13.0-V batteries of a 716 k
tino4ka555 [31]

Answer:

\mathbf{ current(I) =1766.67 \ A}

Explanation:

Given that:

The air resistance and friction = 700 N

The gravity caused force = 716 × 9.8 = 7016.8

Total force = (7016.8 + 700) N

Total force = 7716.8 N

∴

13 \times  current(I) \times 0.84 = \dfrac{7716.8 \times 300}{2 \times 60}

current(I) \times 10.92= 19292

current(I) = \dfrac{19292}{10.92}

\mathbf{ current(I) =1766.67 \ A}

8 0
2 years ago
A body of mass 2kg moves round a circle of radius 5m with a constant speed of 10m/s. Calculate the force toward the centre of th
antiseptic1488 [7]

Answer:

F = 5

Explanation:

F = m x v^2/r = 2 x 10^2/5 =200/5 = 40 (N)

5 0
2 years ago
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