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NikAS [45]
3 years ago
13

Tech A says the leads on a multimeter are negative and positive. Tech B says the test leads on an oscilloscope that we normally

use are yellow, blue, and green. Who is correct?
Physics
1 answer:
tangare [24]3 years ago
8 0

Answer:

Tech B

Explanation:

An oscilloscope is a measuring instrument for electronics. It represents a graph of amplitude on the vertical axis and time on the horizontal axis. It is widely used by students, designers, engineers in the field of electronics. It is often complemented by a multimeter, a power supply and a function generator or arbitrary.

As usual:

The Temperature palette or lead uses grading to indicate the frequency of occurrence, with warm colors such as yellow indicating red / frequently occurring events and cold colors such as blue / green indicating rarely occurring events

The spectral palette or lead uses grading to indicate the frequency of occurrence with cold colors such as blue that indicate events that occur frequently and warm colors such as red that indicate events that occur rarely.

The normal Palette uses the default color channel (such as yellow for channel one), along with the gray scale to indicate the frequency of occurrence, where the events that occur frequently are bright.

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3 years ago
What causes the change in momentum?
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Answer:

See explanation

Explanation:

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3 0
3 years ago
If you run the 100 m track at a velocity of 5.0 m/s, what is the time needed?
Tresset [83]
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8 0
3 years ago
A 1.51 kg ball and a 1.97 kg ball are connected by a 1.63 m long rigid, massless rod. The rod is rotating clockwise about its ce
Eddi Din [679]

Answer:

T = 1.205\,N\cdot m

Explanation:

Needed torque can be estimated by means of the Theorem of Angular Momentum Conservation and Impact Theorem. The center of mass of the system is:

\bar r = \frac{(0\,m)\cdot (1.51\,kg)+(1.63\,kg)\cdot (1.97\,kg)}{1.51\,kg+1.97\,kg}

\bar r = 0.923\,m

Let assume that both masses can be modelled as particles, then:

[(1.51\,kg)\cdot (0.923\,m)^{2} + (1.97\,kg)\cdot (0.707\,m)^{2}]\cdot (38\,\frac{rev}{min} )\cdot (\frac{2\pi\,rad}{1\,rev} )\cdot (\frac{1\,min}{60\,s} ) -T\cdot (7.5\,s) = 0\,\frac{kg\cdot m^{2}}{s}

The torque needed to stop the system is:

T = 1.205\,N\cdot m

5 0
3 years ago
An electron de-excites from the fourth quantum level to the third and then directly to the first. Two frequencies of light are e
4vir4ik [10]

Answer:

The answer is explained below.

Explanation:

The energy emitted during the de-excitation of an electron from a higher energy level to a lower energy level is directly proportional to the frequency of the emitted light.

Here, the total sum of the energies of 2 frequencies of light emitted in different stages is equal to the energy of a single frequency of light during the de-excitation of fourth level to ground level directly.

Hence the total sum of of the frequencies of 2 lights emitted in different stages is equal to the frequency of single frequency of light emitted during the de-excitation  from fourth level to ground level directly.

The some of the energies of 2 frequencies emitted by one electron is equal to the energy of a single frequency when electron jumps directly.

6 0
3 years ago
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