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NikAS [45]
3 years ago
13

Tech A says the leads on a multimeter are negative and positive. Tech B says the test leads on an oscilloscope that we normally

use are yellow, blue, and green. Who is correct?
Physics
1 answer:
tangare [24]3 years ago
8 0

Answer:

Tech B

Explanation:

An oscilloscope is a measuring instrument for electronics. It represents a graph of amplitude on the vertical axis and time on the horizontal axis. It is widely used by students, designers, engineers in the field of electronics. It is often complemented by a multimeter, a power supply and a function generator or arbitrary.

As usual:

The Temperature palette or lead uses grading to indicate the frequency of occurrence, with warm colors such as yellow indicating red / frequently occurring events and cold colors such as blue / green indicating rarely occurring events

The spectral palette or lead uses grading to indicate the frequency of occurrence with cold colors such as blue that indicate events that occur frequently and warm colors such as red that indicate events that occur rarely.

The normal Palette uses the default color channel (such as yellow for channel one), along with the gray scale to indicate the frequency of occurrence, where the events that occur frequently are bright.

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Explain how the aperture geometry relates to the<br> diffraction pattern.
konstantin123 [22]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

how the aperture geometry relates to the

diffraction pattern:

Diffraction is the spreading out of waves as they pass through an aperture or around objects.it occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of  the incident wave.For every small aperture sizes,the vast majority of the wave is blocked.For large apertures the wave passes by or through the obstacle without any significant of diffraction.

            in an aperture with width smaller than the wavelength,the wave transmitted through the aperture spreads all the way around the behave like a point sources of waves.

                             single slit diffraction pattern

The diffraction pattern made by waves passing through a slit of width \alpha (larger than∫) can be understood by imagining a series of point sources all in phase along the width of the slit.The waves moving directly forward are all in phase,so they from a large central maximum.

                 if the waves travels at an angle Ф from the normal to the slit,then there is a path difference x between the waves production at the two end of the slit.

           x=a sinΦ

The path difference between the top and middle waves is λ/2 then they are exactly out of phase and cancel each other out. This happens to all consecutive pairs of waves (the ones produced by the second source from the top and the second source past the middle etc.)at the angle so there is no resultant wave at this angle.Thus a minimum is the diffraction pattern is obtained at

                                                   λ=α sinθ

Now slit can be divided into four equal sections and the pairing of sources to give destructive interference can be repeated for the top two section ,which is identical to the result of pairing off matching sources in the bottom two sections.in this case we obtained from the minimum.

             λ/2=α/4 sinθ

we can divided the slit aperture into six equal sections and pair off sources in the top two divisions and then the bottom two,to give destructive interference for every matched pair.The minimum of intensity are obtained at angles

                      nλ = α sinθ

where n is an integer (1,2,......),  but not n=0.There is a maximum of intensity in the center of the pattern. This process only gives the position of the minima,does not work for positions of the maxima,and so does not give the intensities of the maxima.

5 0
2 years ago
The specific heat of acetic acid is 2.07 J/gºC. If 1150 J of heat is
Doss [256]

Answer:

12.3 °C

Explanation:

Q=m*Cp*ΔT-->

1150=45*2.07*ΔT-->

ΔT=1150/93.15-->

ΔΤ=12.3 °C

4 0
3 years ago
1. A 46000N helicopter feels a net force of 9200N. What litt force is exerted by the air on the propellers?
Lina20 [59]

Answer:

Force exerted by the air on the propellers = 46000 - 9200

= 36800 N

Hope this helps!

4 0
3 years ago
25 PTS
yarga [219]
The answer would be C
7 0
3 years ago
How do characteristics help you to classify seeds?
Artyom0805 [142]

Characteristics help us to classify seeds because different plants have different features.

<h3>How are characteristics used to identify and classify plants?</h3>

The divisions classify plants that are based on whether they reproduce by spores or seeds. Spore-bearing plants include ferns, club mosses, and horsetail while on the other hand, Seed-bearing plants are divided into gymnosperms and angiosperms. Different plants have different characteristics and features so on the basis of these characteristics we can easily classify seeds whether they belong from angiosperm and gymnosperm.

So we can conclude that characteristics help us to classify seeds because different plants have different features.

Learn more about seeds here: brainly.com/question/18799172

#SPJ1

5 0
1 year ago
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