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2 years ago

What happens to the direction of an object as an unbalanced force acts on it? Give an example

Physics

2 answers:

xz_007 [3.2K]2 years ago

8 0

Hello :)

Answer:

When an unbalanced force acts on an object, the side with the greater force's direction makes the object move along its direction. For example, when two cars collide on a head-on collision, both vehicles will move in the direction that the vehicle with the greater force is moving in.

Pie2 years ago

5 0

Answer:

When an unbalanced force acts on a body the side with the greater force's dircetion makes the object move along its direction

Also to find the net force acting on the bofldy you can subtract the two force acting on the body

In case of balanced force the net force will always be 0

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A ball is dropped from rest at point O (height unknown). After falling for some time, it passes by a window of height 3 m and it

Usimov [2.4K]

Answer:

Part a)

$\Delta v_{down} = 4.8 m/s$

Part b)

$v_a = 3.71 m/s$

Explanation:

Since ball is dropped under uniform gravity

so here we can say that the distance of 3 m moved by the ball under uniform acceleration is given as

$d = (\frac{v_f + v_i}{2})t$

so we have

$3 = (\frac{v_f + v_i}{2})(0.49)$

$v_f + v_i = 12.24$

also we know that

$v_f - v_i = at$

$v_f - v_i = (9.81)(0.49)$

$v_f - v_i = 4.81$

now we will have

$v_f = 8.52 m/s$

$v_i = 3.71 m/s$

Part a)

$\Delta v_{down} = v_b - v_a$

$\Delta v_{down} = 8.52 - 3.71$

$\Delta v_{down} = 4.8 m/s$

Part b)

speed at the top of the window is

$v_a = 3.71 m/s$

3 0

2 years ago

A child of mass 47 kg sits on the edge of a merry-go-round with radius 1.3 m and moment of inertia 56.3953 kg m2 . The merrygo-r

lakkis [162]

Answer:

$F=156.416\ N$ the child have to exert this much amount of force radially to stay on the wheel.

Explanation:

Given:

mass of the child, $m=47\ kg$

radius of the merry-go round wheel, $r=1.3\ m$

moment of inertia of the wheel, $I=56.3953\ kg.m^2$

angular velocity of the wheel, $\omega=1.6\ rad.s^{-1}$

Since the child is sitting on the edge of the rotating wheel the child will feel and outward throwing force called centrifugal force.

Centrifugal force is mathematically given as:

$F=m.r.\omega^2$

$F=47\times 1.3\times 1.6^2$

$F=156.416\ N$ the child have to exert this much amount of force radially to stay on the wheel.

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3 years ago

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It should be A sorry if I’m wrong

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3 years ago

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Characteristics of abuse of Narcotics include ______.

Elden [556K]

Are there any options?

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3 years ago

Analyze the image below and answer the question that follows.

goldenfox [79]

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3 years ago