Answer:
Explanation:
(a) Work done, W = 1.82 x 10^4 J
(b) internal energy, U = - 4.07 x 10^4 J ( as it decreases)
(c) According to the first law of thermodynamics
Q = W + U
Q = 1.82 x 10^4 - 4.07 x 10^4
Q = - 2.25 x 10^4 J
Explanation:
There are three forces on the bicycle:
Reaction force Rp pushing up at P,
Reaction force Rq pushing up at Q,
Weight force mg pulling down at O.
There are four equations you can write: sum of the forces in the y direction, sum of the moments at P, sum of the moments at Q, and sum of the moments at O.
Sum of the forces in the y direction:
Rp + Rq − (15)(9.8) = 0
Rp + Rq − 147 = 0
Sum of the moments at P:
(15)(9.8)(0.30) − Rq(1) = 0
44.1 − Rq = 0
Sum of the moments at Q:
Rp(1) − (15)(9.8)(0.70) = 0
Rp − 102.9 = 0
Sum of the moments at O:
Rp(0.30) − Rq(0.70) = 0
0.3 Rp − 0.7 Rq = 0
Any combination of these equations will work.
Answer:
wave number = 0.3348 * 10⁻⁸ cm⁻¹
Explanation:
Given data:
K = 4.808 * 10^2 N/m
<u>Determine the wave number for the infrared absorption</u>
considering vibrational Spectre
k' = 2n / λ ---- ( 1 )
λ = c / v ----- ( 2 )
v = √k / u --- ( 3 )
where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency, k = force constant, u = reduced mass
u = 1.90415 for D35Cl
Input equations 2 and 3 into equation 1 to get the final equation
K' = 2n/c * √k / u
= ( 2 * 3.14 ) / 2.98 * 10^8 ] * (√ 4.808 * 10^2 / 1.90415 )
= 33.486 * 10⁻⁸ m⁻¹ ≈ 0.3348 * 10⁻⁸ cm⁻¹
P1i+p2i =p1f +p2f where p is momentum and i denotes initial, f denotes final, and 1 and 2 refers to the object number. If the object stops, their velocity is 0 and p1f and p2f also equal 0.
p=mass x velocity
We have p1i=-p2i
100v1i=-(200) (-10÷3.6)
Note: 10÷3.6 is 10km/hr in m/s
Note: The velocity of the second object ifs negative because I said the velocity of the first object was positive and the second object is travelling in the opposite direction
So v1i=20/3.6=5.56m/s