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qaws [65]
3 years ago
7

Quick Check:

Physics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

Quick Check:

12-17-20

Conservation of Energy

In the use of an energy resource like coal, do you get all

the energy back in one form(100%)? (circle one)

Yes

No

Explanation:

Not sure

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Scarcity is not usually a problem in economics true or false
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False because the allocation rule of "first come-first served" promotes productive cooperation.
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If a car has an initial velocity of 20 m/s and accelerates at 2.0 m/s² for 100 m, what is its final velocity?
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Answer:

28.28 ms-1

Explanation:

v² = u² + 2as

v² = 20² + 2× 2×100

v² = 800

v = 28.28 ms-1

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A glacier can travel over the surface of earth and reshape it. the chart describes three things a glacier can do.which terms bes
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Why are identical bulbs arranged in a series circuit with a battery less bright than those arranged in a parallel circuit with t
tatuchka [14]

Explanation:

Resistors connected in series obey the following equation:

R_{\rm eq} = R_1 + R_2 + R_3 + ...

Resistors connected in parallel obey the following equation:

\frac{1}{R_{\rm eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ...

The total current of the circuit will obey the Ohm's Law: V = IR. And the current will be divided across the resistors (bulbs) depending on their resistances. So, if a bulb has a higher resistance, then its current will be lesser, and it will be less bright. If a bulb has a lower resistance, then its current will be higher, and it will be brighter.

According to the above resistances connected in series and parallel, clearly, the resistances (bulbs) connected in series will have more resistance in total, and therefore less current will flow across them, and they will be less bright.

6 0
3 years ago
An 8 g bullet leaves the muzzle of a rifle with
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Answer: 1872 N

Explanation:

This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:

V^{2}=V_{o}^{2} + 2ad (1)

F=ma (2)

Where:

V=611.9 m/s is the bullet's final speed (when it leaves the muzzle)

V_{o}=0 is the bullet's initial speed (at rest)

a is the bullet's acceleration

d=0.8 m is the distance traveled by the bullet before leaving the muzzle

F is the force

m=8 g \frac{1 kg}{1000 g}=0.008 kg is the mass of the bullet

Knowing this, let's begin by isolating a from (1):

a=\frac{V^{2}}{2d} (3)

a=\frac{(611.9 m/s)^{2}}{2(0.8 m)} (4)

a=234013.5063 m/s^{2} \approx 2.34(10)^{5} m/s^{2} (5)

Substituting (5) in (2):

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Finally:

F=1872 N

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