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charle [14.2K]
3 years ago
14

Need to know the process.

Chemistry
1 answer:
erastova [34]3 years ago
7 0
To calculate ΔH of reaction, let's use the following formula

ΔH of reaction= [ΔH of products] - [ΔH of reactants]

note: keep in mind that you have to multiply each value by its coefficient. 

ΔH of reaction= [ ΔH CO2 + ΔH H2O + ΔH Na2CO3] - [ΔH NaHCO3]

ΔH of reaction = [ -393.5 + -241.8 + -1130.9] - [ 2 x -947.7] 

ΔH of reaction= 129.2 kJ
since ΔH is positive, the reaction is endothermic
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Waves carry energy from one place to another.

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Explanation:

i hope it helps

that's my answer

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3 0
2 years ago
This is a solution whose solvent is water.
Anastasy [175]
It would be the Aqueous solution
8 0
3 years ago
(3 Points)
prisoha [69]
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5 0
3 years ago
Read 2 more answers
N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?
just olya [345]

Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}

(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

7 0
3 years ago
Read 2 more answers
Which shows the weight of an atom?
sammy [17]

Answer:

The atomic mass

Explanation:

3 0
2 years ago
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